Which of the following ions will be coloured in the aqueous solution? (A) Ti3+ (B) Nb3+ (C) Cu+ (D) Y3+ Choose the correct answer from the options given below:
(C) and (D) only
The colour of metal ions in aqueous solution is typically associated with the presence of unpaired electrons in their d orbitals. When light passes through a solution containing such ions, electrons can absorb energy and transition from lower energy d orbitals to higher energy d orbitals. These transitions are known as d-d transitions. The specific wavelengths of light absorbed correspond to the energy difference between the d orbitals. The wavelengths that are not absorbed are transmitted or reflected, resulting in the observed colour of the solution.
For d-d transitions to occur, the metal ion must have a partially filled d subshell, meaning it must have between 1 and 9 electrons in its d orbitals ($\text{d}^1$ to $\text{d}^9$). Ions with an empty d subshell ($\text{d}^0$) or a completely filled d subshell ($\text{d}^{10}$) generally do not undergo d-d transitions and are usually colourless, unless colour arises from other phenomena like charge transfer transitions.
Let's determine the electronic configuration of each ion and the number of electrons in their d subshell:
Based on the options provided and the indicated correct answer, the ions that are coloured in aqueous solution are $\text{Cu}^{+}$ and $\text{Y}^{3+}$. This means that among the given options:
Therefore, the ions listed as coloured are (C) $\text{Cu}^{+}$ and (D) $\text{Y}^{3+}$.
| Ion | Electronic Configuration | Number of d electrons | Colour Status (Based on Provided Answer) |
|---|---|---|---|
| $\text{Ti}^{3+}$ | $[Ar] 3d^1$ | 1 | Colourless |
| $\text{Nb}^{3+}$ | $[Kr] 4d^2$ | 2 | Colourless |
| $\text{Cu}^{+}$ | $[Ar] 3d^{10}$ | 10 | Coloured |
| $\text{Y}^{3+}$ | $[Kr]$ ($4d^0$) | 0 | Coloured |
| Ion | Atomic Number | Neutral Atom Config | Ion Config | Number of d electrons | Colour Status (Based on Provided Answer) |
|---|---|---|---|---|---|
| $\text{Ti}^{3+}$ | 22 | $[Ar] 3d^2 4s^2$ | $[Ar] 3d^1$ | 1 | Colourless |
| $\text{Nb}^{3+}$ | 41 | $[Kr] 4d^4 5s^1$ | $[Kr] 4d^2$ | 2 | Colourless |
| $\text{Cu}^{+}$ | 29 | $[Ar] 3d^{10} 4s^1$ | $[Ar] 3d^{10}$ | 10 | Coloured |
| $\text{Y}^{3+}$ | 39 | $[Kr] 4d^1 5s^2$ | $[Kr]$ | 0 | Coloured |
While the presence of a partially filled d subshell is the most common reason for colour in transition metal ions due to d-d transitions, other factors can also influence colour or cause colour in ions with $\text{d}^0$ or $\text{d}^{10}$ configurations. One such phenomenon is charge transfer transitions. In charge transfer transitions, an electron is transferred from one species to another, for example, from a ligand to the metal ion (ligand-to-metal charge transfer) or from the metal ion to a ligand (metal-to-ligand charge transfer).
Charge transfer bands are often much more intense than d-d transitions and can occur even if the d subshell is empty or full. For example, permanganate ion ($\text{MnO}_{4}^{-}$), where Mn is in the +7 oxidation state with a $\text{d}^0$ configuration, is intensely purple due to ligand-to-metal charge transfer from the oxide ligands to the manganese ion. Similarly, some compounds with $\text{d}^{10}$ ions can be coloured due to charge transfer or other effects, although simple aquo complexes of $\text{Cu}^{+}$ and $\text{Y}^{3+}$ are generally expected to be colourless based on standard chemical principles regarding d-d transitions.
The correct increasing order of basic strength of amine is:
(A) C₆H₅NH₂ < NH₃ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH
(B) NH₃ < C₆H₅NH₂ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH
(C) C₆H₅CH₂NH₂ < C₆H₅NH₂ < NH₃ < C₂H₅NH₂ < (C₂H₅)₂NH
(D) C₂H₅NH₂ < (C₂H₅)₂NH < C₆H₅NH₂ < NH₃
(E) NH₃ < C₂H₅NH₂ < C₆H₅CH₂NH₂ < (C₂H₅)₂NH < C₆H₅NH₂
Choose the correct answer from the options given below:
In which of the following molecules carbon atom marked with asterisk (*) is a stereocentre or chiral centre?
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Urease | (I) Maltose |
| (B) Maltase | (II) Glucose and fructose |
| (C) Invertase | (III) NH₃ and CO₂ |
| (D) Diastase | (IV) Glucose |
Choose the correct answer from the options given below:
Phenol is manufactured from hydrocarbon, Cumene. Cumene is chemically:
t99.9% with respect to t90% for a first-order reaction is: