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Question

Which of the following curves represent a first order reaction?

The correct answer is

Understanding First Order Reaction Kinetics

A first order reaction is a reaction whose rate depends on the concentration of only one reactant raised to the power of one. The rate law for a first order reaction involving a reactant A is given by:

\begin{equation*} \text{Rate} = k[A] \end{equation*}

where $[A]$ is the concentration of reactant A and $k$ is the rate constant.

Integrated Rate Law for First Order Reactions

To understand how concentration changes with time in a first order reaction, we look at the integrated rate law. The differential rate law is $\frac{d[A]}{dt} = -k[A]$. Integrating this gives:

\begin{equation*} \ln[A]_t - \ln[A]_0 = -kt \end{equation*}

Rearranging this equation, we get:

\begin{equation*} \ln[A]_t = -kt + \ln[A]_0 \end{equation*}

This equation is in the form of a straight line, $y = mx + c$, where:

  • $y = \ln[A]_t$ (natural logarithm of the concentration of A at time $t$)
  • $m = -k$ (the slope, which is a negative constant)
  • $x = t$ (time)
  • $c = \ln[A]_0$ (the y-intercept, natural logarithm of the initial concentration of A)

Therefore, plotting $\ln[A]_t$ against time $(t)$ for a first order reaction yields a straight line with a negative slope.

Analyzing the Given Reaction Curves

Let's examine the types of curves typically associated with different reaction orders when plotted in specific ways:

  • Zero Order Reaction: $[A]_t = -kt + [A]_0$. A plot of $[A]_t$ versus $t$ is a straight line with a negative slope.
  • First Order Reaction: $\ln[A]_t = -kt + \ln[A]_0$. A plot of $\ln[A]_t$ versus $t$ is a straight line with a negative slope.
  • Second Order Reaction (Type 1: Rate = k[A]2): $\frac{1}{[A]_t} = kt + \frac{1}{[A]_0}$. A plot of $\frac{1}{[A]_t}$ versus $t$ is a straight line with a positive slope.

We are looking for a curve that represents a first order reaction. Based on the integrated rate law, the characteristic linear plot for a first order reaction is $\ln[A]_t$ vs. $t$. Let's consider the shapes of the curves provided as options:

Option 1: Shows a linear relationship, possibly Rate vs. Concentration, which could be first order (Rate = k[A]). However, the question asks for curves representing the reaction itself, usually concentration or a function of concentration vs. time.

Option 2: Shows a curve increasing with time. This could represent the concentration of a product over time, but the shape is not typically linear or a simple exponential for product formation in a standard plot type.

Option 3: Shows a curve decreasing with time in a non-linear fashion. This could represent the concentration of a reactant decaying over time for a first or second-order reaction, but neither gives a straight line when plotting concentration vs. time.

Option 4: Shows a straight line with a negative slope. This is characteristic of a plot where the y-axis represents $\ln[Reactant]$ and the x-axis represents time for a first order reaction, or potentially concentration vs time for a zero-order reaction. Given the context of reaction orders and common plots, a straight line often implies a specific manipulation of the concentration term (like $\ln[A]$ or $1/[A]$) plotted against time.

Comparing the options with the expected plots for different reaction orders, the straight line with a negative slope (Option 4) is the definitive representation of a first order reaction when the y-axis is $\ln[Reactant]$ and the x-axis is time.

Conclusion on First Order Reaction Curve

The curve that represents a first order reaction is the one showing a linear relationship with a negative slope when the natural logarithm of the reactant concentration is plotted against time. Among the given options, only Option 4 depicts a straight line with a negative slope, which fits this description for a first order reaction.

Reaction Order Integrated Rate Law Plot Expected Graph Shape
Zero Order $[A]_t$ vs. Time ($t$) Straight line with negative slope
First Order $\ln[A]_t$ vs. Time ($t$) Straight line with negative slope
Second Order (Rate=k[A]2) $\frac{1}{[A]_t}$ vs. Time ($t$) Straight line with positive slope

Revision Table: Key Kinetic Plots

Plot (y vs. x) Slope Intercept Reaction Order Indicated
$[A]$ vs. $t$ $-k$ $[A]_0$ Zero Order
$\ln[A]$ vs. $t$ $-k$ $\ln[A]_0$ First Order
$\frac{1}{[A]}$ vs. $t$ $k$ $\frac{1}{[A]_0}$ Second Order

Additional Information on First Order Reaction Kinetics

The half-life ($t_{1/2}$) of a first order reaction is independent of the initial concentration. It is given by the formula:

\begin{equation*} t_{1/2} = \frac{\ln(2)}{k} = \frac{0.693}{k} \end{equation*}

This is a unique characteristic of first order reactions and is often used to identify them. Radioactive decay is a common example of a process that follows first order kinetics.

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Important Questions from Organic Compounds Containing Nitrogen

  1. The correct increasing order of basic strength of amine is:

    (A) C₆H₅NH₂ < NH₃ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH

    (B) NH₃ < C₆H₅NH₂ < C₆H₅CH₂NH₂ < C₂H₅NH₂ < (C₂H₅)₂NH

    (C) C₆H₅CH₂NH₂ < C₆H₅NH₂ < NH₃ < C₂H₅NH₂ < (C₂H₅)₂NH

    (D) C₂H₅NH₂ < (C₂H₅)₂NH < C₆H₅NH₂ < NH₃

    (E) NH₃ < C₂H₅NH₂ < C₆H₅CH₂NH₂ < (C₂H₅)₂NH < C₆H₅NH₂

    Choose the correct answer from the options given below:

  2. In which of the following molecules carbon atom marked with asterisk (*) is a stereocentre or chiral centre?

  3. Match List-I with List-II:

    List-IList-II
    (A) Urease(I) Maltose
    (B) Maltase(II) Glucose and fructose
    (C) Invertase(III) NH₃ and CO₂
    (D) Diastase(IV) Glucose

    Choose the correct answer from the options given below:

  4. Phenol is manufactured from hydrocarbon, Cumene. Cumene is chemically:

  5. t99.9% with respect to t90% for a first-order reaction is:

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