To find the compound with a formula unit mass of 100 u, we need to calculate the mass for each option using the atomic masses of the constituent elements.
Approximate atomic masses are:
| Element | Atomic Mass (u) |
|---|---|
| Na | 23.0 |
| Mg | 24.3 |
| C | 12.0 |
| O | 16.0 |
| Ca | 40.1 |
| Cl | 35.5 |
Formula Unit Mass (MgO) = Atomic Mass (Mg) + Atomic Mass (O)
$Mass_{MgO} = 24.3 \text{ u} + 16.0 \text{ u} = 40.3 \text{ u}$
Formula Unit Mass ($CaCl_2$) = Atomic Mass (Ca) + 2 * Atomic Mass (Cl)
$Mass_{CaCl_2} = 40.1 \text{ u} + 2 \times 35.5 \text{ u} = 40.1 \text{ u} + 71.0 \text{ u} = 111.1 \text{ u}$
Formula Unit Mass ($Na_2CO_3$) = 2 * Atomic Mass (Na) + Atomic Mass (C) + 3 * Atomic Mass (O)
$Mass_{Na_2CO_3} = (2 \times 23.0 \text{ u}) + 12.0 \text{ u} + (3 \times 16.0 \text{ u})$
$Mass_{Na_2CO_3} = 46.0 \text{ u} + 12.0 \text{ u} + 48.0 \text{ u} = 106.0 \text{ u}$
Formula Unit Mass ($CaCO_3$) = Atomic Mass (Ca) + Atomic Mass (C) + 3 * Atomic Mass (O)
$Mass_{CaCO_3} = 40.1 \text{ u} + 12.0 \text{ u} + (3 \times 16.0 \text{ u})$
$Mass_{CaCO_3} = 40.1 \text{ u} + 12.0 \text{ u} + 48.0 \text{ u} = 100.1 \text{ u}$
Comparing the calculated masses:
The compound with a formula unit mass closest to 100 u is $CaCO_3$. Therefore, $CaCO_3$ is the correct answer.
Which of the following correctly represents the number of atoms in one mole of CH3 OH?
A solution of Gallic acid in ethanol was made by dissolving 0.05 mg in 250 mL of ethanol(w/v). This solution in ppm would be ______________.
The molarity of a solution containing 5 gram of Sodium hydroxide (NaOH) in 500 millilitre solution is : (Take atomic weights of elements as : Na = 23, O = 16, H = 1)