Which of the following best describes the relationship between distance, time, and speed when a body is NOT accelerating?
\(\text{time} = \frac{\text{distance}}{\text{speed}}\)
The fundamental formula for speed is:
\[ \text{speed} = \frac{\text{distance}}{\text{time}} \]
Rearranging to solve for time:
\[ \text{time} = \frac{\text{distance}}{\text{speed}} \]
Thus, the correct answer is \( \text{time} = \frac{\text{distance}}{\text{speed}} \).
Important Questions from Kinematic equations for uniformly accelerated motion
- A ball is thrown vertically upward with a speed of 40 m/s. The time taken by the ball to reach the maximum height would be approximately
A tennis ball is thrown in the vertically upward direction and the ball attains a maximum height of 20 m. The ball was thrown approximately with an upward velocity of
A particle experiences constant acceleration for 20 s after starting from rest. If it travels a distance X 1, in the first 10 s and distance X 2in the remaining 10 s, then which of the following is true?
- A ball thrown up vertically returns to the ground after 10 second. Find the velocity with which it was thrown up? (if g = 10 m/s2).
If the distance travelled by a body in the $n^{th}$ second is given by $(7 + 5n)$ m, then find the initial velocity and acceleration of the body respectively.
