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Question

Which among the following is a proposition in predicate logic?

The correct answer is

(x) (f\(\supset\)  Gx)

Understanding Propositions in Predicate Logic

Predicate logic builds upon propositional logic by adding more expressive power through the use of variables, predicates, and quantifiers. This allows us to represent statements about objects and their properties or relationships in a more detailed way.

What is a Proposition in Predicate Logic?

A proposition in predicate logic is a statement that can be definitively determined as either true or false. It must be a complete assertion. Key components include:

  • Predicates: These are like functions that return true or false depending on their arguments. For example, $f(x)$ could mean "x is female", and $G(x)$ could mean "x is a student". In the options provided, notation like $f_x$ and $G_x$ is used, typically representing predicates applied to a variable like $x$.
  • Variables: Symbols like $x$, $y$ that stand for objects within a specified domain.
  • Quantifiers: These symbols specify the scope or range of variables:
    • Universal Quantifier: Symbolized as $(x)$ or $\( \forall x \)$, meaning "for all x" in the domain.
    • Existential Quantifier: Symbolized as $(∃x)$ or $\( \exists x \)$, meaning "there exists at least one x" in the domain.
  • Logical Connectives: Symbols such as implication ($\( \supset \)$, meaning "if... then...") and conjunction ($\( \cdot \)$, meaning "and").
  • Constants: Specific objects, like $a$ appearing in option 2.

For a statement involving variables to be considered a proposition, all its variables must be bound by quantifiers. Statements involving only constants or free of variables can also be propositions if they make a complete assertion.

Analyzing the Provided Options

Let's examine each option to determine which one represents a proposition in predicate logic:

Option 1 & 4: $\( (x) (f_x \supset G_x) \)$

This expression utilizes the universal quantifier $(x)$, signifying "for all x". It links two predicates, $f_x$ and $G_x$, using the implication connective $\( \supset \)$. This structure represents a statement like "For all x, if property f holds for x, then property G also holds for x." This is a standard and well-formed proposition in predicate logic because the variable $x$ is universally quantified, meaning its scope is fully defined.

Option 2: $\( (\exists x) (f_a \cdot G_x) \)$

This option employs the existential quantifier $(∃x)$, indicating "there exists an x". It combines a predicate $f_a$ (where $a$ is likely a constant) with the predicate $G_x$, connected by the conjunction symbol $\( \cdot \)$. This forms a complete assertion: "There exists an x such that f_a is true and G_x is true." Since all variables ($x$) are quantified or the statement involves only constants (like $a$), this is also a valid proposition.

Option 3: $\( (\exists x) (f_y \cdot G_x) \)$

In this statement, the existential quantifier $(∃x)$ is present. However, the predicate $f_y$ contains a variable $y$ that is not bound by any quantifier within this expression. If $y$ is a free variable (meaning its meaning or scope isn't determined here), the entire expression might not be a complete proposition but rather a predicate expression. While it could be part of a larger logical statement, as presented in isolation, it is less clearly a standalone proposition compared to the others.

Option 5:

This option is empty and therefore cannot represent a proposition.

Conclusion on Predicate Logic Propositions

Based on the analysis, a proposition in predicate logic requires a complete, verifiable assertion. This means variables must be properly quantified. Option 4, $\( (x) (f_x \supset G_x) \)$, clearly demonstrates the structure of a universally quantified proposition. It is a complete statement about all elements in the domain, making it a valid proposition in predicate logic.

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Important Questions from Miscellaneous

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