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Question

Which among the following has the same dimension as that of energy?

This question was previously asked in
SSC Stenographer 2019 Previous Year Paper (24-Dec-2020) (Shift 2)
The correct answer is

Torque

Understanding Dimensions in Physics

In physics, dimensions are used to characterize the nature of a physical quantity. They are expressed in terms of fundamental dimensions like Mass ([M]), Length ([L]), and Time ([T]). Comparing the dimensions of different physical quantities helps us understand their relationships and can also be useful in checking the validity of equations.

Determining the Dimension of Energy

Energy is the ability to do work. The dimension of energy is the same as the dimension of work. Work ($W$) is defined as force ($F$) multiplied by distance ($d$).

The dimension of force is derived from Newton's second law, $F = ma$, where $m$ is mass and $a$ is acceleration.

  • Dimension of Mass ([M]) = $[M]$
  • Dimension of Length ([L]) = $[L]$
  • Dimension of Time ([T]) = $[T]$
  • Dimension of Acceleration ($a$) = $\frac{\text{Dimension of Velocity}}{\text{Dimension of Time}} = \frac{[L T^{-1}]}{[T]} = [L T^{-2}]$
  • Dimension of Force ($F$) = Dimension of Mass $\times$ Dimension of Acceleration = $[M] \times [L T^{-2}] = [M L T^{-2}]$

Now, the dimension of Work ($W$) or Energy ($E$) is:

Dimension of Energy = Dimension of Force $\times$ Dimension of Distance = $[M L T^{-2}] \times [L] = [M L^2 T^{-2}]$

So, the dimension of energy is $[M L^2 T^{-2}]$.

Analyzing Dimensions of the Given Options

Let's find the dimensions of each given option:

Dimension of Moment of Inertia

Moment of inertia ($I$) is a measure of an object's resistance to changes in its rotation rate. For a point mass $m$ at a distance $r$ from the axis of rotation, $I = mr^2$.

Dimension of Moment of Inertia = Dimension of Mass $\times$ (Dimension of Distance)$^2 = [M] \times [L]^2 = [M L^2]$

Dimension of Torque

Torque ($\tau$) is the rotational equivalent of force. It is often calculated as the force applied multiplied by the perpendicular distance from the pivot point to the line of action of the force ($\tau = rF\sin\theta$). Since $\sin\theta$ is dimensionless, the dimension depends on $r$ and $F$.

Dimension of Torque = Dimension of Distance $\times$ Dimension of Force = $[L] \times [M L T^{-2}] = [M L^2 T^{-2}]$

Dimension of Linear Momentum

Linear momentum ($p$) is defined as the product of mass and velocity ($p = mv$).

Dimension of Linear Momentum = Dimension of Mass $\times$ Dimension of Velocity = $[M] \times [L T^{-1}] = [M L T^{-1}]$

Dimension of Angular Momentum

Angular momentum ($L$) is the rotational equivalent of linear momentum. For a point mass, it is the product of linear momentum and the perpendicular distance from the pivot point ($L = rp\sin\theta$). Alternatively, it is the product of moment of inertia and angular velocity ($L = I\omega$). Using $L = I\omega$:

  • Dimension of Moment of Inertia ($I$) = $[M L^2]$
  • Dimension of Angular Velocity ($\omega$) = $\frac{\text{Dimension of Angle}}{\text{Dimension of Time}}$. Angle (in radians) is dimensionless. So, Dimension of Angular Velocity = $[T^{-1}]$

Dimension of Angular Momentum = Dimension of Moment of Inertia $\times$ Dimension of Angular Velocity = $[M L^2] \times [T^{-1}] = [M L^2 T^{-1}]$

Comparison of Dimensions

Let's compare the dimensions in a table:

Physical Quantity Dimension
Energy $[M L^2 T^{-2}]$
Moment of Inertia $[M L^2]$
Torque $[M L^2 T^{-2}]$
Linear Momentum $[M L T^{-1}]$
Angular Momentum $[M L^2 T^{-1}]$

Comparing the dimensions, we can see that Torque has the same dimension as Energy, which is $[M L^2 T^{-2}]$. Although torque and energy have the same dimensions, they are different physical quantities representing different concepts (rotational force effect vs. capacity to do work). The dimensional similarity arises from their definitions involving force and distance, but the way these quantities are combined is different (scalar product for work/energy, vector product for torque).

Conclusion

Based on the dimensional analysis, Torque has the same dimension as Energy.

Revision Table: Dimensions of Key Quantities

Quantity Formula (Example) Dimensions
Mass $m$ $[M]$
Length $L$ $[L]$
Time $t$ $[T]$
Velocity $v = d/t$ $[L T^{-1}]$
Acceleration $a = v/t$ $[L T^{-2}]$
Force $F = ma$ $[M L T^{-2}]$
Work / Energy $W = Fd$ $[M L^2 T^{-2}]$
Torque $\tau = rF\sin\theta$ $[M L^2 T^{-2}]$
Linear Momentum $p = mv$ $[M L T^{-1}]$
Angular Velocity $\omega = \theta/t$ $[T^{-1}]$
Moment of Inertia $I = mr^2$ $[M L^2]$
Angular Momentum $L = I\omega$ or $L=rp\sin\theta$ $[M L^2 T^{-1}]$

Additional Information on Dimensions and Units

Dimensional analysis is a powerful tool in physics. It can be used to:

  • Check the consistency of equations: Both sides of a physics equation must have the same dimensions.
  • Derive relationships between physical quantities: Sometimes, you can predict the form of an equation up to a dimensionless constant using dimensional analysis.
  • Understand the nature of physical quantities: Quantities with the same dimensions might be related, although they represent different physical concepts (like energy and torque).

It's important not only to know the dimensions but also the standard units (like SI units) for these quantities:

  • Energy: Joule (J) or Newton-meter (Nm)
  • Torque: Newton-meter (Nm)
  • Moment of Inertia: kilogram meter squared (kg m²)
  • Linear Momentum: kilogram meter per second (kg m/s)
  • Angular Momentum: kilogram meter squared per second (kg m²/s)

Notice that the unit Newton-meter (Nm) is used for both energy and torque, reflecting their shared dimension, but they represent different physical ideas (scalar work vs. vector rotational effect).

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Important Questions from Momentum and Energy

  1. What would be the momentum of the bullet and the gun before firing?
  2. Light with an energy flux of 500 kW/m2 falls for 5 minutes at normal incidence on a non-reflecting circular surface with a radius of 10 cm. The total momentum delivered to this surface has a magnitude of ______.

  3. If the linear momentum of a moving object gets doubled due to application of a force, then its kinetic energy will

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