When the minute hand covers a distance of 1 hr 10 min, then what is the angular distance covered by it?
(c) 420°
Clock problems often involve calculating the angular distance covered by the hands. The minute hand is one of the fastest moving hands on a standard clock face, completing a full circle in one hour.
To solve this problem, we need to determine the angular speed of the minute hand and then calculate the total angle covered for the given duration.
The minute hand completes one full revolution, which is 360 degrees, in 60 minutes.
Therefore, the angular speed of the minute hand can be calculated as:
Angular speed = $\frac{\text{Total degrees in a circle}}{\text{Total time for one revolution}}$
Angular speed = $\frac{360^{\circ}}{60 \text{ minutes}}$
Angular speed = $6^{\circ}\text{ per minute}$
This means that for every minute that passes, the minute hand moves 6 degrees.
The question states that the minute hand covers a distance equivalent to a duration of 1 hour and 10 minutes.
Total time in minutes = 60 minutes + 10 minutes = 70 minutes.
Now that we have the total time in minutes and the angular speed of the minute hand, we can calculate the total angular distance covered.
Angular distance = Angular speed $\times$ Total time
Angular distance = $6^{\circ}\text{/minute} \times 70 \text{ minutes}$
Angular distance = $420^{\circ}$
So, when the minute hand covers a duration of 1 hour and 10 minutes, it moves through an angle of 420 degrees.
| Parameter | Value |
|---|---|
| Time Duration | 1 hour 10 minutes |
| Time in Minutes | 70 minutes |
| Minute Hand Angular Speed | $6^{\circ}$/minute |
| Angular Distance Covered | $420^{\circ}$ |
Let's compare our calculated angular distance with the given options:
Our calculated angular distance of 420° matches option (c).
| Clock Hand | Time for 360° | Angular Speed |
|---|---|---|
| Minute Hand | 60 minutes | $360^{\circ} / 60 \text{ min} = 6^{\circ}\text{/min}$ |
| Hour Hand | 12 hours (720 minutes) | $360^{\circ} / 12 \text{ hr} = 30^{\circ}\text{/hr}$ or $360^{\circ} / 720 \text{ min} = 0.5^{\circ}\text{/min}$ |
| Second Hand | 60 seconds (1 minute) | $360^{\circ} / 60 \text{ sec} = 6^{\circ}\text{/sec}$ |
Angular distance refers to the angle through which an object rotates or moves along a circular path. In the context of a clock, as the hands move, they trace out angles from their starting position.
The concept of angular speed is crucial for solving clock problems. It is the rate at which the angle changes over time.
Calculating angular distance is a direct application of the relationship between speed, time, and distance, adapted for rotational motion.
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