Let the original number be represented by the variable $x$. The problem states that "one-third of a number is increased by 55, the result is 77". This can be written as an algebraic equation:
$ \frac{1}{3}x + 55 = 77 $
To find the value of $x$, we first isolate the term with $x$ by subtracting 55 from both sides of the equation:
$ \frac{1}{3}x = 77 - 55 $
$ \frac{1}{3}x = 22 $
Next, we solve for $x$ by multiplying both sides by 3:
$ x = 22 \times 3 $
$ x = 66 $
So, the original number is 66.
The question asks for the sum of the digits of the original number (66). The digits are 6 and 6.
Sum of digits = $6 + 6 = 12$.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.
How many composite numbers are there from 53 to 97 ?