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Question

When ω/ωn = 1, the transmissibility is

where ω = frequency of excitation, rad/s

ωn = Natural frequency, rad/s

The correct answer is

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Understanding Transmissibility at Resonance

Transmissibility (TR) is a key concept in vibration analysis. It measures how effectively vibrations are transmitted through a system. Specifically, it's the ratio of the amplitude of the output (force transmitted or motion) to the amplitude of the input (exciting force or motion).

Transmissibility Formula

For a viscously damped single-degree-of-freedom system, the transmissibility (TR) is given by the formula:

$$TR = \frac{\sqrt{1 + (2\zeta)^2}}{\sqrt{(1 - (\omega/\omega_n)^2)^2 + (2\zeta(\omega/\omega_n))^2}}$$

Where:

  • $TR$ is the transmissibility.
  • $\zeta$ is the damping ratio (a measure of how quickly vibrations decay).
  • $\omega$ is the frequency of the external excitation (in rad/s).
  • $\omega_n$ is the natural frequency of the system (in rad/s).

Analyzing the Condition: $\omega/\omega_n = 1$

The condition $\omega/\omega_n = 1$ signifies that the system is excited at its natural frequency. This condition is known as resonance.

Let's substitute $\omega/\omega_n = 1$ into the transmissibility formula:

$$TR = \frac{\sqrt{1 + (2\zeta)^2}}{\sqrt{(1 - (1)^2)^2 + (2\zeta(1))^2}}$$

Simplifying the expression:

$$TR = \frac{\sqrt{1 + 4\zeta^2}}{\sqrt{(1 - 1)^2 + (2\zeta)^2}}$$

$$TR = \frac{\sqrt{1 + 4\zeta^2}}{\sqrt{0^2 + (2\zeta)^2}}$$

$$TR = \frac{\sqrt{1 + 4\zeta^2}}{\sqrt{4\zeta^2}}$$

$$TR = \frac{\sqrt{1 + 4\zeta^2}}{2\zeta}$$

Transmissibility Behavior at Resonance

Now, consider the behavior of the transmissibility as the damping ratio $\zeta$ changes, particularly when it is very small (approaching zero), which is common in many physical systems.

  • Numerator: As $\zeta \to 0$, the term $4\zeta^2$ approaches 0. So, the numerator $\sqrt{1 + 4\zeta^2}$ approaches $\sqrt{1 + 0} = \sqrt{1} = 1$.
  • Denominator: As $\zeta \to 0$, the denominator $2\zeta$ also approaches 0.

When the numerator approaches 1 and the denominator approaches 0, the fraction $\frac{1}{0}$ tends towards infinity.

Therefore, when $\omega/\omega_n = 1$ (resonance), the transmissibility:

$$TR \to \infty$$

This means that at resonance, with very little damping, the amplitude of the transmitted force or motion can become extremely large, potentially leading to system failure.

Conclusion

When the excitation frequency ($\omega$) equals the natural frequency ($\omega_n$), or $\omega/\omega_n = 1$, the transmissibility approaches infinity (or proportionality, denoted by $\prop$), especially in systems with low damping.

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Important Questions from Transmissibility and Magnification Factor

  1. The Transmissibility of a vibrating system, for the values of (ω/ωn) >√2, will be

  2. A vibrating system having a mass of 30 kg is supported by 4 springs, each having a stiffness of k. The system runs at 420 rpm. If only 10% of the shaking force is allowed to be transmitted to the supporting structure, then the value of stiffness k will be close to:

  3. For a single degree of freedom viscous damped system, if the frequency ratio is greater than √2, it implies that:

  4. Dynamic Magnification Factor is computed as:

  5. A single degree of freedom system having mass 1 kg and stiffness 10 kN/m initially at rest is subjected to an impulse force of magnitude 5 kN for 10-4 seconds. The amplitude in mm of the resulting free vibration is

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