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Question

When electric current is passed through a wire, the amount of heat produced in a wire depends upon _______.

I. Length

II. Thickness

The correct answer is

Both I and II

Heat Produced in a Wire

When electric current flows through a wire, some of the electrical energy is converted into heat energy. This phenomenon is known as the heating effect of electric current or Joule heating. The amount of heat produced in a wire depends on several factors, as described by Joule's Law of Heating.

Joule's Law of Heating

Joule's Law states that the heat (H) produced in a conductor is directly proportional to:

  • The square of the electric current (I) flowing through it.
  • The resistance (R) of the conductor.
  • The time (t) for which the current flows.

Mathematically, this is expressed as:

\[\text{H = I}^2\text{Rt}\]

To understand how the length and thickness of the wire affect the heat produced, we need to consider how these properties influence the wire's resistance (R).

Resistance of the Wire

The electrical resistance (R) of a wire depends on its material, length, and cross-sectional area. The formula for resistance is:

\[\text{R = ρ}\frac{\text{L}}{\text{A}}\]

Where:

  • $\rho$ (rho) is the resistivity of the material (a constant for a given material).
  • L is the length of the wire.
  • A is the cross-sectional area of the wire.

The thickness of the wire is directly related to its cross-sectional area. A thicker wire has a larger cross-sectional area.

Length's Influence on Heat

Let's analyze how the length of the wire affects the heat produced:

  • From the resistance formula $\text{R = ρ}\frac{\text{L}}{\text{A}}$, it is clear that resistance (R) is directly proportional to the length (L) of the wire. This means if you increase the length of the wire, its resistance increases.
  • According to Joule's Law, $\text{H = I}^2\text{Rt}$, heat (H) is directly proportional to resistance (R).
  • Therefore, if the length of the wire increases, its resistance increases, leading to more heat being produced, assuming the current and time remain constant.

Thickness's Influence on Heat

Now, let's look at how the thickness of the wire affects the heat produced:

  • Thickness relates to the cross-sectional area (A) of the wire. A thicker wire has a larger cross-sectional area.
  • From the resistance formula $\text{R = ρ}\frac{\text{L}}{\text{A}}$, resistance (R) is inversely proportional to the cross-sectional area (A). This means if the cross-sectional area increases (i.e., the wire becomes thicker), its resistance decreases.
  • According to Joule's Law, $\text{H = I}^2\text{Rt}$, heat (H) is directly proportional to resistance (R).
  • Therefore, if the thickness of the wire increases (meaning its area increases), its resistance decreases, leading to less heat being produced, assuming the current and time remain constant.

Conclusion

Based on the analysis of Joule's Law and the factors affecting electrical resistance, both the length and the thickness of a wire significantly influence the amount of heat produced when electric current is passed through it. Thus, the heat produced depends upon both I. Length and II. Thickness.

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Important Questions from Resistance and Resistivity

  1. Which of the following metals has the lowest electrical resistivity?

  2. A uniform wire of resistance 9Ω is bent in the form of an equilateral triangle. Find the effective resistance across a side of the triangle.

  3. The value of carbon resistance is 54 × 103 Ω. The percentage tolerance is 5%. What is the colour code sequence of carbon resistance?

  4. Which of the following relations are wrong?

    I. The specific conductance is given by the relation \(k = \frac{1}{R}\left( {l/A} \right)\)

    II. The equivalent conducting is given by the relation \(\lambda = \frac{{100\;K}}{C}\)

    III. The specific resistance is given by the relation \(\rho = \frac{{Rl}}{A}\)

  5. A current is flowing through a metallic wire. If the wire is heated, which quantities change?

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