When a stone thrown directly upwards reaches the top, it: A. Velocity and acceleration are zero. B. The velocity is zero and the acceleration is about 10 m/s 2. C. Velocity is about 10 m/s and acceleration is zero. D. The velocity is about 10 m/s and the acceleration remains the same.
B
When a stone is thrown directly upwards, it moves against the force of gravity. Gravity causes a constant downward acceleration. As the stone rises, its upward velocity decreases due to this downward acceleration. Eventually, it reaches its highest point before starting to fall back down.
At the very peak of its trajectory, the stone momentarily stops changing direction. It is no longer moving upwards and has not yet started moving downwards. This brief moment of rest means its instantaneous velocity is zero.
Acceleration is the rate of change of velocity. While the stone's velocity is momentarily zero at the peak, the force of gravity is still acting on it. Gravity exerts a constant downward pull, resulting in a constant downward acceleration, known as the acceleration due to gravity. This acceleration (g) is approximately $9.8 \, \text{m/s}^2$ on Earth, often rounded to $10 \, \text{m/s}^2$ for simplicity in many problems. The acceleration due to gravity does not disappear or become zero just because the object's velocity is momentarily zero.
Let's evaluate each option based on our understanding of motion under gravity:
This is incorrect. While the velocity is zero at the peak, the acceleration due to gravity is definitely not zero; it is still acting downwards.
This is consistent with our physics understanding. The velocity is momentarily zero at the highest point, and the acceleration due to gravity is approximately $10 \, \text{m/s}^2$ (downwards, though the option only gives magnitude).
This is incorrect. The velocity at the peak is zero, not $10 \, \text{m/s}$. The acceleration at the peak is about $10 \, \text{m/s}^2$, not zero.
This is incorrect regarding velocity; the velocity is zero at the peak. The statement about acceleration remaining the same is true in magnitude (it's always about $10 \, \text{m/s}^2$), but the velocity claim makes the option incorrect.
Based on the analysis, Option B accurately describes the velocity and acceleration of a stone thrown directly upwards when it reaches the top.
| Point in Trajectory | Velocity | Acceleration |
|---|---|---|
| Going Up | Decreasing (upwards) | Constant ($\approx 10 \, \text{m/s}^2$ downwards) |
| At the Top (Peak) | Zero (instantaneously) | Constant ($\approx 10 \, \text{m/s}^2$ downwards) |
| Coming Down | Increasing (downwards) | Constant ($\approx 10 \, \text{m/s}^2$ downwards) |
| Concept | Explanation | At the Peak |
|---|---|---|
| Velocity | Speed and direction of motion | Zero (momentarily) |
| Acceleration | Rate of change of velocity | Due to gravity ($\approx 10 \, \text{m/s}^2$ downwards) |
| Force of Gravity | Pull towards the Earth | Always acting downwards |
A stone thrown directly upwards is a classic example of one-dimensional projectile motion under constant acceleration (due to gravity). Here are a few key points:
It's a common misconception that acceleration is zero when velocity is zero. This is only true if the net force on the object is zero at that moment. For a stone in free flight, the force of gravity is always present, resulting in constant acceleration.
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