When a proton injected in magnetic field moves perpendicular to the lines of force, it follows
circular path
When a force of constant magnitude acts perpendicular to the velocity of a particle, it acts as a centripetal force, causing the particle to move in a circular path. Equating the magnetic force to the centripetal force ( F_c = (mv^2)/(r) ), where m is the mass of the proton and r is the radius of the circular path:
Important Questions from Motion in a Magnetic Field
Which of the following is the correct expression for cyclotron frequency?
The radius of curvature of a charged particle's passage in a homogeneous magnetic field is proportional to:
What is the period of revolution T of charge - q1 if a particle of mass m carrying a charge - q1 starts moving around a fixed charge + q2 along a circular path of radius r?
A proton and an alpha particle moving with same kinetic energy enter in the region of uniform magnetic field perpendicular to it. The ratio of radii of their trajectories will be:
- A 2.0 m long metallic rod is rotated with an angular frequency of 100 rad/s about an axis normal to the rod and passing through its one end. A uniform magnetic field of 2.0 T exits parallel to the axis. The emf induced between the two ends of the rod is:
