What will be the time taken by light to travel 2cm thickness of glass of refractive index 1.5?
2.5×10−10s
Understanding how light travels through different materials requires knowing the speed of light in that material. This speed is related to the speed of light in a vacuum by the material's refractive index.
The speed of light in a medium (\(v\)) is slower than the speed of light in a vacuum (\(c\)). The relationship between them is given by the refractive index (\(n\)) of the medium:
\(n = \frac{c}{v}\)
From this, we can find the speed of light in the glass:
\(v = \frac{c}{n}\)
The speed of light in a vacuum is approximately \(c = 3 \times 10^8\) m/s.
We know that time taken (\(t\)) to travel a distance (\(d\)) at a constant speed (\(v\)) is given by:
\(t = \frac{d}{v}\)
Substitute the expression for \(v\) from the refractive index relationship into the time equation:
\(t = \frac{d}{\left(\frac{c}{n}\right)}\)
\(t = \frac{d \times n}{c}\)
First, convert the thickness from centimeters to meters:
\(d = 2 \text{ cm} = 2 \times 10^{-2} \text{ m}\)
Now, plug the values into the formula \(t = \frac{d \times n}{c}\):
\(t = \frac{(2 \times 10^{-2} \text{ m}) \times 1.5}{3 \times 10^8 \text{ m/s}}\)
\(t = \frac{3 \times 10^{-2} \text{ m}}{3 \times 10^8 \text{ m/s}}\)
Simplify the expression:
\(t = \left(\frac{3}{3}\right) \times 10^{-2 - 8} \text{ s}\)
\(t = 1 \times 10^{-10} \text{ s}\)
The time taken by light to travel 2 cm thickness of glass with a refractive index of 1.5 is \(1 \times 10^{-10}\) seconds.
| Concept | Formula | Notes |
|---|---|---|
| Speed of light in vacuum | \(c \approx 3 \times 10^8\) m/s | Constant reference speed |
| Refractive Index | \(n = \frac{c}{v}\) | Ratio of speed in vacuum to speed in medium |
| Speed in Medium | \(v = \frac{c}{n}\) | Derived from refractive index definition |
| Time, Distance, Speed | \(t = \frac{d}{v}\) | Basic kinematic relation |
| Time in Medium (combined) | \(t = \frac{d \times n}{c}\) | Useful direct formula |
The refractive index is a dimensionless quantity that tells us how much the speed of light is reduced when it passes through a medium compared to its speed in a vacuum. A higher refractive index means light travels slower in that medium.
This change in speed is also responsible for the phenomenon of refraction, where light bends as it crosses the boundary between two different media.
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Match List - I with List - II
| List-I | List-II |
|---|---|
| (A) Microwave | (I) Radar System for Aircraft Navigation |
| (B) UV Rays | (II) To study crystal structure |
| (C) X-Rays | (III) Radioactive decay of Nucleus |
| (D) Gamma-Rays | (IV) Lasik eye surgery |
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