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Question

What will be the Modulus of the complex number (5 - 5i)/(3 - 4i)?

The correct answer is √2

Modulus of a Complex Number Division

The question asks for the modulus of the complex number given by the expression &(\frac{5 - 5i}{3 - 4i}&). We need to find the absolute value of this complex number.

Complex Number Modulus Formula

For a complex number in the standard form &($z = x + iy$&), where &($x$) is the real part and &($y$) is the imaginary part, the modulus (or absolute value) is calculated using the formula:

&(|z| = \sqrt{x^2 + y^2}&)

Alternatively, for the division of two complex numbers, &($z_1 / z_2$&), the modulus can be calculated as the ratio of their moduli:

&(|z_1 / z_2| = |z_1| / |z_2|&)

Calculating Modulus Using Division Property

Let &($z_1 = 5 - 5i$) and &($z_2 = 3 - 4i$). We can calculate the modulus of each complex number separately and then divide.

  • Modulus of the numerator, &($z_1 = 5 - 5i$&):
    Here, &($x = 5$) and &($y = -5$).
    &(|z_1| = \sqrt{5^2 + (-5)^2} = \sqrt{25 + 25} = \sqrt{50}&)
  • Modulus of the denominator, &($z_2 = 3 - 4i$&):
    Here, &($x = 3$) and &($y = -4$).
    &(|z_2| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25}&)

Now, divide the moduli:

&(\left|\frac{5 - 5i}{3 - 4i}\right| = \frac{|5 - 5i}}{|3 - 4i|} = \frac{\sqrt{50}}{\sqrt{25}}&)

Simplify the expression:

&(\frac{\sqrt{50}}{\sqrt{25}} = \sqrt{\frac{50}{25}} = \sqrt{2}&)

Calculating Modulus After Simplifying the Complex Number

Another approach is to first simplify the complex number expression by multiplying the numerator and denominator by the conjugate of the denominator (&($3 + 4i$)):

&(\frac{5 - 5i}{3 - 4i} = \frac{(5 - 5i)(3 + 4i)}{(3 - 4i)(3 + 4i)}&)

Multiply the numerator:

&((5 - 5i)(3 + 4i) = 5(3) + 5(4i) - 5i(3) - 5i(4i)&)
&(= 15 + 20i - 15i - 20i^2&)
Since &($i^2 = -1$), we get:
&(= 15 + 5i - 20(-1) = 15 + 5i + 20 = 35 + 5i&)

Multiply the denominator (using &((a-bi)(a+bi) = a^2 + b^2)&):

&((3 - 4i)(3 + 4i) = 3^2 + (-4)^2 = 9 + 16 = 25&)

The simplified complex number is:

&(\frac{35 + 5i}{25} = \frac{35}{25} + \frac{5i}{25} = \frac{7}{5} + \frac{1}{5}i&)

Now, calculate the modulus of this simplified complex number &($z = \frac{7}{5} + \frac{1}{5}i$). Here, &($x = \frac{7}{5}$) and &($y = \frac{1}{5}$).

&(|z| = \sqrt{\left(\frac{7}{5}\right)^2 + \left(\frac{1}{5}\right)^2}&)

&(|z| = \sqrt{\frac{49}{25} + \frac{1}{25}}&)

&(|z| = \sqrt{\frac{49 + 1}{25}} = \sqrt{\frac{50}{25}}&)

&(|z| = \sqrt{2}&)

Both methods yield the same result.

The modulus of the complex number &(\frac{5 - 5i}{3 - 4i}$) is &(\sqrt{2}$).

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Important Questions from Properties of Complex Numbers

  1. If z z̅ = |z + z̅ |, where z = x + iy, i = \(\sqrt{-1}\), then the locus of z is a pair of:

  2. What is the value of \(\sqrt{12+5 i}+\sqrt{12-5 i}\) where \(i=\sqrt{-1}\) ?

  3. If z is a complex number such that \(\frac{z-1}{z+1}\) is purely imaginary, then what is |z| equal to ?

  4. What is the real part of (sin x + icos x) 3

  5. What is z 1+ z 2+ z 3equal to?

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