What will be the Magnetomotive force in a coil having 250 turns and carrying a current of 10 A ?
2500 AT
Calculating Magnetomotive Force (MMF) in a Coil
The Magnetomotive Force (MMF) is the magnetic equivalent of electromotive force (EMF) in an electrical circuit. It is the force that establishes magnetic flux in a magnetic circuit. The MMF is directly proportional to the number of turns in a coil and the current flowing through it.
The formula to calculate Magnetomotive Force (MMF) is:
$$MMF = N \times I$$
Where:
- MMF is the Magnetomotive Force, measured in Ampere-Turns (AT).
- N is the number of turns in the coil.
- I is the current flowing through the coil, measured in Amperes (A).
In this question, we are given the following information:
- Number of turns (N) = 250 turns
- Current (I) = 10 A
Now, we can substitute these values into the formula to calculate the Magnetomotive Force:
$$MMF = 250 \text{ turns} \times 10 \text{ A}$$
$$MMF = 2500 \text{ AT}$$
Therefore, the Magnetomotive force in the coil having 250 turns and carrying a current of 10 A is 2500 AT.
The unit of Magnetomotive Force is Ampere-Turns (AT), which reflects the product of the current and the number of turns creating the magnetic field.
Important Questions from Magnetostatics
In electromagnetic induction, according to Fleming’s right-hand rule, the forefinger represents _________.
Which of the following statements are true with Faraday’s laws of electromagnetic induction?
A magnetic pressure which sets up or tends to set up flux in a magnetic circuit is called-
A coil of 600 turns and of resistance of 20 Ω is wound uniformly over a steel ring of mean circumference 30 cm and cross sectional area 9 cm2. If the relative permeability of the ring is 1600. Find the value of reluctance.
The unit of magnetic flux density is
