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Question

What will be the Magnetomotive force in a coil having 250 turns and carrying a current of 10 A ?

The correct answer is

2500 AT

Calculating Magnetomotive Force (MMF) in a Coil

The Magnetomotive Force (MMF) is the magnetic equivalent of electromotive force (EMF) in an electrical circuit. It is the force that establishes magnetic flux in a magnetic circuit. The MMF is directly proportional to the number of turns in a coil and the current flowing through it.

The formula to calculate Magnetomotive Force (MMF) is:

$$MMF = N \times I$$

Where:

  • MMF is the Magnetomotive Force, measured in Ampere-Turns (AT).
  • N is the number of turns in the coil.
  • I is the current flowing through the coil, measured in Amperes (A).

In this question, we are given the following information:

  • Number of turns (N) = 250 turns
  • Current (I) = 10 A

Now, we can substitute these values into the formula to calculate the Magnetomotive Force:

$$MMF = 250 \text{ turns} \times 10 \text{ A}$$

$$MMF = 2500 \text{ AT}$$

Therefore, the Magnetomotive force in the coil having 250 turns and carrying a current of 10 A is 2500 AT.

The unit of Magnetomotive Force is Ampere-Turns (AT), which reflects the product of the current and the number of turns creating the magnetic field.

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Important Questions from Magnetostatics

  1. In electromagnetic induction, the expression for induced voltage is based on ______.
  2. ______ is the flux-producing ability of an electric current in a magnetic circuit.

  3. The source of a magnetic field is

  4. Hysteresis loss can be reduced by

  5. A current flows in a conductor from east to west. The direction of magnetic fields at a point above the conductor is

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