What is the VSWR when feeding an RF signal to a 55 Ω load through a coaxial cable of characteristic impedance 50 Ω?
1.1
Understanding Voltage Standing Wave Ratio (VSWR) is crucial in RF (Radio Frequency) engineering, especially when dealing with transmission lines like coaxial cables connected to a load. VSWR indicates how well a load is impedance-matched to the transmission line. A perfect match results in a VSWR of 1, meaning no power is reflected back towards the source.
To calculate the VSWR, we first need to determine the reflection coefficient ($\Gamma$). The formula for the reflection coefficient is:
$$\Gamma = \frac{\text{Z}_{\text{L}} - \text{Z}_0}{\text{Z}_{\text{L}} + \text{Z}_0}$$
Once the reflection coefficient is known, the VSWR can be calculated using the following formula:
$$\text{VSWR} = \frac{1 + |\Gamma|}{1 - |\Gamma|}$$
Where $|\Gamma|$ is the magnitude of the reflection coefficient.
Let's apply these formulas to the given problem:
Substitute the given values into the reflection coefficient formula:
$$\Gamma = \frac{55 \, \Omega - 50 \, \Omega}{55 \, \Omega + 50 \, \Omega}$$
$$\Gamma = \frac{5 \, \Omega}{105 \, \Omega}$$
$$\Gamma = \frac{1}{21}$$
Now, we find the magnitude of the reflection coefficient:
$$|\Gamma| = \left| \frac{1}{21} \right| \approx 0.047619$$
Next, substitute the value of $|\Gamma|$ into the VSWR formula:
$$\text{VSWR} = \frac{1 + |\Gamma|}{1 - |\Gamma|}$$
$$\text{VSWR} = \frac{1 + 0.047619}{1 - 0.047619}$$
$$\text{VSWR} = \frac{1.047619}{0.952381}$$
$$\text{VSWR} \approx 1.1$$
The calculated VSWR for feeding an RF signal to a 55 Ω load through a coaxial cable with a characteristic impedance of 50 Ω is approximately 1.1.
This value of 1.1 indicates a relatively good match, as it is close to the ideal VSWR of 1. A VSWR of 1.1 means that roughly 0.26% of the incident power is reflected back. While not a perfect match, it is generally considered acceptable in many RF applications.
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