What is the value of \(? = \frac{{ta{n^2}{{60}^0} - 2si{n^2}{{45}^0}}}{{cos{{24}^0}cos{{37}^0}coses{{53}^0}cos{{60}^0}cosec{{66}^0} + si{n^2}{{60}^0}}}\)
The question asks us to find the value of a complex trigonometric expression involving various angles. The expression is given as:
\[ ? = \frac{{ta{n^2}{{60}^0} - 2si{n^2}{{45}^0}}}{{cos{{24}^0}cos{{37}^0}coses{{53}^0}cos{{60}^0}cosec{{66}^0} + si{n^2}{{60}^0}}} \]To solve this, we need to evaluate the numerator and the denominator separately using standard trigonometric values and properties of complementary angles.
The numerator is \({\tan^2}{{60}^0} - 2{\sin^2}{{45}^0}\). We need the standard values for \(\tan 60^\circ\) and \(\sin 45^\circ\).
Now, let's calculate the squared terms:
Substitute these values into the numerator expression:
\[ \text{Numerator} = 3 - 2 \times \frac{1}{2} = 3 - 1 = 2 \]So, the value of the numerator is 2.
The denominator is \({\cos{{24}^0}\cos{{37}^0}\coses{{53}^0}\cos{{60}^0}\cosec{{66}^0} + si{n^2}{{60}^0}}\). This consists of two parts: a product of trigonometric terms and a squared sine term.
The first part is \({\cos{{24}^0}\cos{{37}^0}\coses{{53}^0}\cos{{60}^0}\cosec{{66}^0}}\). We can use complementary angle identities here. Recall that:
Observe the angles:
We can rewrite \(\cosec 53^\circ\) and \(\cosec 66^\circ\):
Substitute these back into the product:
\[ \cos{{24}^0}\cos{{37}^0}(\sec{{37}^0})\cos{{60}^0}(\sec{{24}^0}) \]Rearrange the terms to group complementary functions:
\[ (\cos{{24}^0}\sec{{24}^0})(\cos{{37}^0}\sec{{37}^0})\cos{{60}^0} \]Using the identity \(\cos \theta \sec \theta = 1\), this simplifies to:
\[ (1)(1)\cos{{60}^0} \]The value of \(\cos 60^\circ\) is \(\frac{1}{2}\).
So, the first part of the denominator is \(1 \times 1 \times \frac{1}{2} = \frac{1}{2}\).
The second part of the denominator is \({\sin^2}{{60}^0}\).
The denominator is the sum of Part 1 and Part 2:
\[ \text{Denominator} = \frac{1}{2} + \frac{3}{4} \]To add these fractions, find a common denominator, which is 4:
\[ \text{Denominator} = \frac{2}{4} + \frac{3}{4} = \frac{2+3}{4} = \frac{5}{4} \]So, the value of the denominator is \(\frac{5}{4}\).
The expression is the numerator divided by the denominator:
\[ ? = \frac{\text{Numerator}}{\text{Denominator}} = \frac{2}{\frac{5}{4}} \]To divide by a fraction, multiply by its reciprocal:
\[ ? = 2 \times \frac{4}{5} = \frac{8}{5} \]The value \(\frac{8}{5}\) can also be written as a mixed number:
\[ \frac{8}{5} = 1 \frac{3}{5} \]Thus, the value of the given trigonometric expression is \(1\frac{3}{5}\).
| Component | Calculation | Value |
|---|---|---|
| Numerator | \({\tan^2}{{60}^0} - 2{\sin^2}{{45}^0} = (\sqrt{3})^2 - 2\left(\frac{1}{\sqrt{2}}\right)^2\) | \(3 - 2(\frac{1}{2}) = 3 - 1 = 2\) |
| Denominator (Part 1) | \({\cos{{24}^0}\cos{{37}^0}\coses{{53}^0}\cos{{60}^0}\cosec{{66}^0}}\) | \((\cos{{24}^0}\sec{{24}^0})(\cos{{37}^0}\sec{{37}^0})\cos{{60}^0} = 1 \times 1 \times \frac{1}{2} = \frac{1}{2}\) |
| Denominator (Part 2) | \({\sin^2}{{60}^0} = \left(\frac{\sqrt{3}}{2}\right)^2\) | \(\frac{3}{4}\) |
| Total Denominator | Part 1 + Part 2 | \(\frac{1}{2} + \frac{3}{4} = \frac{2}{4} + \frac{3}{4} = \frac{5}{4}\) |
| Final Value | Numerator / Denominator | \(\frac{2}{5/4} = 2 \times \frac{4}{5} = \frac{8}{5}\) or \(1\frac{3}{5}\) |
| Angle (\(\theta\)) | \(\sin \theta\) | \(\cos \theta\) | \(\tan \theta\) |
|---|---|---|---|
| \(45^\circ\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | 1 |
| \(60^\circ\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) | \(\sqrt{3}\) |
| Identity | Description |
|---|---|
| \(\cos(90^\circ - \theta) = \sin \theta\) | Cosine of a complementary angle is sine of the angle. |
| \(\cosec(90^\circ - \theta) = \sec \theta\) | Cosecant of a complementary angle is secant of the angle. |
| \(\sec \theta = \frac{1}{\cos \theta}\) | Secant is the reciprocal of cosine. |
| \(\cosec \theta = \frac{1}{\sin \theta}\) | Cosecant is the reciprocal of sine. |
| \(\cos \theta \sec \theta = 1\) | Product of cosine and secant of the same angle is 1. |
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