What is the value of ‘a’ in the below equation? {(5 × 5 × 5 × 5 × 5 × 5) 5× (5 × 5 × 5 × 5 × 5) 8} ÷ (5 × 5) = (625) a
17
The problem asks us to find the value of 'a' in a given equation involving powers of the number 5. To solve this, we need to simplify both sides of the equation using the rules of exponents.
The given equation is:
$\{(5 \times 5 \times 5 \times 5 \times 5 \times 5)^{5} \times (5 \times 5 \times 5 \times 5 \times 5)^{8}\} \div (5 \times 5) = (625)^{a}$
Let's first rewrite the terms using exponential notation:
Substitute these exponential forms back into the original equation:
$\{(5^6)^{5} \times (5^5)^{8}\} \div 5^2 = (5^4)^{a}$
We will use the following exponent rules:
Let's simplify the left side of the equation first:
Inside the curly braces, we have $(5^6)^5$ and $(5^5)^8$. Apply the power of a power rule:
So the equation becomes:
$\{5^{30} \times 5^{40}\} \div 5^2 = (5^4)^{a}$
Now, apply the product of powers rule to the terms inside the curly braces:
The equation is now:
$5^{70} \div 5^2 = (5^4)^{a}$
Next, apply the division of powers rule to the left side:
So the left side simplifies to $5^{68}$.
Now let's simplify the right side of the equation, $(5^4)^{a}$, using the power of a power rule:
The equation is now:
$5^{68} = 5^{4a}$
Since the bases on both sides of the equation are equal (both are 5), the exponents must also be equal. Therefore, we can set the exponents equal to each other:
$68 = 4a$
To find the value of 'a', divide both sides by 4:
$a = \frac{68}{4}$
$a = 17$
Thus, the value of 'a' in the equation is 17.
| Step | Expression | Rule Applied | Result |
|---|---|---|---|
| Original Equation | $\{(5^6)^{5} \times (5^5)^{8}\} \div 5^2 = (5^4)^{a}$ | Initial Form | |
| Simplify powers inside braces | $\{5^{30} \times 5^{40}\} \div 5^2 = (5^4)^{a}$ | $(x^m)^n = x^{mn}$ | $5^{30}$, $5^{40}$ |
| Simplify product inside braces | $5^{70} \div 5^2 = (5^4)^{a}$ | $x^m \times x^n = x^{m+n}$ | $5^{70}$ |
| Simplify division on Left Side | $5^{68} = (5^4)^{a}$ | $x^m \div x^n = x^{m-n}$ | $5^{68}$ |
| Simplify Right Side | $5^{68} = 5^{4a}$ | $(x^m)^n = x^{mn}$ | $5^{4a}$ |
| Equate Exponents | $68 = 4a$ | If $x^p = x^q$, then $p = q$ | |
| Solve for 'a' | $a = 17$ | Algebraic step |
The value of 'a' that satisfies the equation is 17.
| Rule Name | Formula | Example |
|---|---|---|
| Product Rule | $x^m \times x^n = x^{m+n}$ | $5^3 \times 5^4 = 5^{3+4} = 5^7$ |
| Quotient Rule | $x^m \div x^n = x^{m-n}$ | $5^7 \div 5^3 = 5^{7-3} = 5^4$ |
| Power Rule (Power of a Power) | $(x^m)^n = x^{mn}$ | $(5^3)^4 = 5^{3 \times 4} = 5^{12}$ |
An exponential equation is an equation where the variable appears in the exponent. To solve simple exponential equations, we often try to make the bases on both sides of the equation the same. Once the bases are equal, we can equate the exponents and solve the resulting linear equation.
Key steps often involve:
This problem specifically tested the application of the product, quotient, and power rules of exponents.
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