Question
What is the value of $(6 + 3i) + (2 + 5i)$?
This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
$8 + 8i$
To find the value of the expression \((6 + 3i) + (2 + 5i)\), we need to add the real parts and the imaginary parts separately.
- \(6 + 2 = 8\) (Adding the real parts)
- \(3i + 5i = 8i\) (Adding the imaginary parts)
Thus, the sum of the complex numbers is:
\((6 + 3i) + (2 + 5i) = 8 + 8i\)
Therefore, the correct answer is \(8 + 8i\).
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Similar Questions
- What is the value of \((2 - 3i) + (3 + 5i)\)
- What is the real part of the number \(15 + 2i\)
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Important Questions from Complex Numbers
- Consider the following complex numbers
$$ z_1 = r_1(\cos \theta_1 + i \, \sin \theta_1) $$
$$ z_2 = r_2(\cos \theta_2 + i \, \sin \theta_2) $$
where $r_1, r_2$ are real numbers, $0 \leq \theta_1 \leq \frac{\pi}{2}$, $0 \leq \theta_2 \leq \frac{\pi}{2}$, and $i = \sqrt{-1}$
If $|z_1 + z_2| = |z_1| + |z_2|$, which one of the following conditions is necessarily CORRECT? - What is the value of \((2 - 3i) + (3 + 5i)\)
- What is the real part of the number \(15 + 2i\)
- What is the real part of the number $5i$?
If Z = 1 + i, where i = √-1, then what is the modulus of \(\rm z+\frac{2}{z}?\)
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