How many geometrical isomers are possible for the complex $ [Pt(NH_3)_2Cl_2] $?
Two
This solution explores the possible geometrical isomers for the coordination complex $ [Pt(NH_3)_2Cl_2] $. Geometrical isomerism occurs when coordination complexes have the same molecular formula and connectivity but differ in the spatial arrangement of their ligands around the central metal atom.
Coordination complexes with a coordination number of 4, like the one in question, often adopt a square planar geometry, especially when the central metal ion is a late transition metal like Platinum (Pt). In a square planar arrangement, ligands occupy positions at the corners of a square around the central metal atom.
For a complex with the general formula $ MA_2B_2 $, where 'M' is the central metal ion, and 'A' and 'B' represent two different types of ligands, geometrical isomerism arises from the relative positions of the identical ligands (A or B).
The complex $ [Pt(NH_3)_2Cl_2] $ features:
These two arrangements represent distinct spatial configurations and are therefore considered different geometrical isomers.
Based on the analysis of the square planar geometry for the $ MA_2B_2 $ type complex $ [Pt(NH_3)_2Cl_2] $, there are two distinct possible geometrical isomers: the *cis* isomer and the *trans* isomer.
Ozone is:
Out of the following which compound does not show sp 3hybridization ?
Which of the following has sp 3d hybridization?
Sulphur exhibit variable Valency due to
The compound 1, 2-butadiene has: