The following table shows the marks obtained by six students A-F in six different subjects S1 to S6 having 160, 160, 120, 120, 200 and 240 as maximum marks, respectively. Based on the data in the table, answer the questions that follow: Students-wise Details of Marks obtained Marks obtained in subject Student S1 (Out of 160) S2 (Out of 160) S3 (Out of 120) S4 (Out of 120) S5 (Out of 200) S6 (Out of 240) A 80 84 66 56 154 150 B 120 100 84 76 136 132 C 128 72 64 70 144 160 D 84 130 96 84 104 168 E 64 128 90 92 174 70 F 70 96 60 56 164 100
108:103
The question asks for the ratio of the total marks scored by student B to the total marks scored by student E across all subjects.
First, sum the marks obtained by student B in all six subjects:
Total marks for Student B = \( 120 + 100 + 84 + 76 + 136 + 132 = 648 \)
Next, sum the marks obtained by student E in all six subjects:
Total marks for Student E = \( 64 + 128 + 90 + 92 + 174 + 70 = 618 \)
Calculate the ratio of Student B's total marks to Student E's total marks:
Ratio = Total Marks of B : Total Marks of E
Ratio = \( 648 : 618 \)
To simplify the ratio, find the greatest common divisor or divide by common factors.
The simplified ratio is \( 108:103 \).
The ratio of the total marks scored by student B to the total marks scored by student E is 108:103.
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