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Question

What is the period of the function f(x) = ln(2 + sin 2x)?

This question was previously asked in
NDA I 2021 GAT Previous Year Paper (18-Apr-2021)
The correct answer is

π

Understanding Function Periodicity

The period of a function \(f(x)\) is the smallest positive value \(T\) such that \(f(x + T) = f(x)\) for all \(x\) in the domain of \(f\). For trigonometric functions, this concept is fundamental.

We are asked to find the period of the function \(f(x) = \ln(2 + \sin 2x)\). This function is composed of an inner trigonometric function, \(\sin 2x\), and outer functions, adding 2 and taking the natural logarithm (\(\ln\)).

Period of the Core Trigonometric Function

The periodicity of \(f(x)\) is primarily determined by the periodicity of its trigonometric component, \(\sin 2x\).

The standard sine function, \(\sin \theta\), has a period of \(2\pi\). This means \(\sin(\theta + 2\pi) = \sin \theta\) for all \(\theta\).

For a function of the form \(\sin(ax + b)\) or \(\cos(ax + b)\), the period is given by \(\frac{2\pi}{|a|}\). In our case, the trigonometric component is \(\sin 2x\). Here, \(a = 2\).

Using the formula, the period of \(\sin 2x\) is:

\(T_{\sin 2x} = \frac{2\pi}{|a|} = \frac{2\pi}{|2|} = \frac{2\pi}{2} = \pi\)

So, the function \(\sin 2x\) repeats its values every \(\pi\) units. This means \(\sin(2(x + \pi)) = \sin(2x + 2\pi)\). Since the sine function has a period of \(2\pi\), \(\sin(2x + 2\pi) = \sin(2x)\).

Effect of Outer Functions on Period

Now consider the full function \(f(x) = \ln(2 + \sin 2x)\).

  • Adding a constant (2) to \(\sin 2x\) shifts the graph vertically but does not change its period. If \(\sin 2x\) repeats every \(\pi\), then \(2 + \sin 2x\) also repeats every \(\pi\). Specifically, \((2 + \sin(2(x+\pi))) = (2 + \sin(2x + 2\pi)) = (2 + \sin 2x)\).
  • Applying the natural logarithm function (\(\ln\)) to \(2 + \sin 2x\) also does not change the period. The natural logarithm function is a monotonic function (it is always increasing). If the input \(y = 2 + \sin 2x\) repeats its sequence of values every \(\pi\), then \(\ln(y) = \ln(2 + \sin 2x)\) will also repeat its sequence of values every \(\pi\), provided that the input \(2 + \sin 2x\) is always within the domain of the logarithm (which it is, since \(-1 \le \sin 2x \le 1\), so \(1 \le 2 + \sin 2x \le 3\), and \(\ln(y)\) is defined for \(y > 0\)).

Therefore, the period of the function \(f(x) = \ln(2 + \sin 2x)\) is the same as the period of \(\sin 2x\).

Determining the Final Period

We found that the period of \(\sin 2x\) is \(\pi\).

Let's verify: \(f(x + \pi) = \ln(2 + \sin(2(x + \pi))) = \ln(2 + \sin(2x + 2\pi))\).

Since \(\sin(\theta + 2\pi) = \sin \theta\), we have \(\sin(2x + 2\pi) = \sin 2x\).

So, \(f(x + \pi) = \ln(2 + \sin 2x) = f(x)\).

This confirms that \(\pi\) is a period. The period of \(\sin 2x\) was \(\pi\), and the outer functions did not reduce this period. Thus, the smallest positive period is \(\pi\).

The period of the function \(f(x) = \ln(2 + \sin 2x)\) is \(\pi\).

Function Component Rule/Period
\(\sin \theta\) Period \(2\pi\)
\(\sin(ax)\) Period \(\frac{2\pi}{|a|}\)
\(\sin(2x)\) Period \(\frac{2\pi}{|2|} = \pi\)
\(g(x) + c\) (if \(g(x)\) has period T) Period T
\(h(g(x))\) (if \(g(x)\) has period T and \(h\) is monotonic) Period T
\(\ln(2 + \sin 2x)\) Period of \(\sin 2x\), which is \(\pi\)

Revision Table: Key Periodic Properties

Function Standard Period
\(\sin x\) \(2\pi\)
\(\cos x\) \(2\pi\)
\(\tan x\) \(\pi\)
\(\csc x\) \(2\pi\)
\(\sec x\) \(2\pi\)
\(\cot x\) \(\pi\)
\(A \cdot f(Bx + C) + D\) where \(f(x)\) has period T \(\frac{T}{|B|}\) (for sin, cos, sec, csc with T=\(2\pi\))
\(\frac{T}{|B|}\) (for tan, cot with T=\(\pi\))

Additional Information on Function Periods

When dealing with functions that are combinations of different types, the period is often determined by the component with the largest period, or the least common multiple (LCM) of the individual periods if they are summed or multiplied. However, in a composition like \(f(g(x))\), if \(g(x)\) has a period \(T_g\), the period of \(f(g(x))\) is often \(T_g\) itself, especially if \(f\) is a single-valued function that doesn't introduce its own, potentially smaller, period (like absolute value can sometimes do) or alter the fundamental frequency of repetition. For monotonic functions like \(\ln(y)\) applied to a periodic input \(y\), the period remains unchanged.

In our case, \(g(x) = 2 + \sin 2x\), and \(f(y) = \ln(y)\). The period of \(\sin 2x\) is \(\pi\), so the period of \(g(x) = 2 + \sin 2x\) is also \(\pi\). Since \(\ln(y)\) is monotonic for \(y > 0\), the function \(f(g(x)) = \ln(2 + \sin 2x)\) retains the period of \(g(x)\), which is \(\pi\).

It is important to find the smallest positive period. Our calculation for \(\sin 2x\) yields the fundamental period \(\pi\). Since the outer functions don't compress the cycle, \(\pi\) is indeed the smallest positive value for which \(f(x + T) = f(x)\).

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Important Questions from Trigonometric Functions

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  2. What is tan 2A equal to?

  3. What is the value of tan 18°?

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  5. What is \(\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }}\) equal to?

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