What is the modulation index in a frequency modulated signal with a carrier frequency of 100 kHz, modulating frequency of 4 kHz and frequency deviation of 50 kHz?
12.5
The question asks us to determine the modulation index for a given frequency modulated signal. Understanding the key parameters involved in frequency modulation is crucial for this calculation.
In frequency modulation (FM), the modulation index, often denoted by the symbol $\beta$ (beta), is a dimensionless quantity that tells us how much the carrier frequency deviates in proportion to the modulating frequency. It's a key parameter that indicates the extent of frequency variation of the carrier wave around its central frequency caused by the modulating signal.
The modulation index ($\beta$) for a frequency modulated signal is calculated using the following formula:
$$\beta = \frac{\text{Frequency Deviation} (\Delta f)}{\text{Modulating Frequency} (f_m)}$$
Where:
From the problem statement, we are provided with the following values:
Now, let's plug the given values into the formula to calculate the modulation index:
$$\beta = \frac{\Delta f}{f_m}$$
Substitute the values:
$$\beta = \frac{50 \text{ kHz}}{4 \text{ kHz}}$$
Performing the division:
$$\beta = 12.5$$
| Parameter | Value |
|---|---|
| Frequency Deviation ($\Delta f$) | 50 kHz |
| Modulating Frequency ($f_m$) | 4 kHz |
| Modulation Index ($\beta$) | 12.5 |
The calculated modulation index of 12.5 indicates that the frequency deviation is 12.5 times the modulating frequency. A higher modulation index generally means a wider bandwidth for the FM signal, and it affects the signal-to-noise ratio and fidelity of the received signal. This value helps in classifying whether the FM signal is narrowband FM (NBFM) or wideband FM (WBFM).
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