All Exams Test series for 1 year @ ₹349 only
Question

What is the minimum bandwidth of Manchester and differential Manchester encoding?

The correct answer is 2 Times that of NRZ

Understanding Bandwidth in Digital Encoding Schemes

Digital data needs to be converted into a signal for transmission over a physical medium. This process is called line coding or digital encoding. Different encoding schemes have different characteristics, including their required bandwidth. Bandwidth is a measure of the range of frequencies a signal occupies or requires for transmission. A higher bandwidth generally means more complex signals or faster changes.

Bandwidth of NRZ Encoding

NRZ (Non-Return to Zero) is a simple encoding scheme. In NRZ-L, a logical 1 is represented by a high voltage level and a logical 0 by a low voltage level. In NRZ-I, the voltage level is inverted at the start of a bit if the bit is a 1, and stays the same if it's a 0.

For NRZ, long sequences of 0s or 1s result in a constant voltage level for an extended period. The minimum frequency component is zero (DC component) for such sequences. However, the fundamental frequency component determining the bandwidth is related to the data rate (R). Theoretically, the minimum bandwidth required for NRZ is $\frac{R}{2}$ Hertz, where R is the bit rate (bits per second). This occurs in cases with alternating 0s and 1s (e.g., 010101...).

Bandwidth of Manchester and Differential Manchester Encoding

Manchester encoding and Differential Manchester encoding are designed to address some of the issues with NRZ, such as the DC component and lack of synchronization transitions during long sequences of identical bits.

  • Manchester Encoding: Each bit is represented by a transition in the middle of the bit interval. For example, a '0' might be represented by a transition from high to low, and a '1' by a transition from low to high. This guarantees a transition in every bit period.
  • Differential Manchester Encoding: A transition occurs in the middle of every bit interval. The encoding of the bit value ('0' or '1') is determined by whether or not there is a transition at the beginning of the bit interval. If the bit is a '0', a transition occurs at the beginning; if it's a '1', no transition occurs at the beginning. This also guarantees a transition in every bit period.

Because both Manchester and Differential Manchester encoding guarantee at least one transition per bit interval (specifically, a transition in the middle), and potentially two transitions (start and middle) in Differential Manchester for a '0', the rate of signal changes is higher and more consistent compared to NRZ. For these schemes, the signal pattern for a bit consists of two levels (high and low) within the bit duration, effectively like sending two NRZ pulses for each bit. This means the signaling rate (baud rate) is twice the bit rate (R).

Since the signaling rate is effectively doubled (2R transitions per second in the worst case, or requiring signaling elements that change at a rate proportional to 2R), the minimum bandwidth required for Manchester and Differential Manchester encoding is approximately twice that of NRZ.

Minimum Bandwidth for Manchester / Differential Manchester $\approx R$ Hertz.

Comparing this to the theoretical minimum bandwidth of NRZ ($\frac{R}{2}$ Hertz), we see that the minimum bandwidth required for Manchester and Differential Manchester is approximately $R / (\frac{R}{2}) = 2$ times that of NRZ.

Comparison Summary

Let's summarize the minimum bandwidth requirements:

Encoding Scheme Minimum Bandwidth (Theoretical) Comparison to NRZ
NRZ $\frac{R}{2}$ 1x
Manchester $R$ 2x
Differential Manchester $R$ 2x

Therefore, the minimum bandwidth required for Manchester and differential Manchester encoding is 2 times that of NRZ.

Revision Table: Digital Encoding Bandwidth

Concept Details
Bandwidth Range of frequencies used by a signal. Higher bandwidth allows for faster signal changes.
NRZ Bandwidth Minimum bandwidth is $\frac{R}{2}$. Efficient in terms of bandwidth but lacks synchronization and has a DC component.
Manchester Bandwidth Minimum bandwidth is $R$. Guarantees a transition in the middle of each bit, aiding synchronization. No DC component. Requires double the bandwidth of NRZ.
Differential Manchester Bandwidth Minimum bandwidth is $R$. Similar properties to Manchester regarding transitions and DC component. Also requires double the bandwidth of NRZ.
R Bit Rate (bits per second).

Additional Information: Bandwidth and Baud Rate

It's important to distinguish between bit rate and baud rate when discussing bandwidth.

  • Bit Rate (R): The number of data bits transmitted per second.
  • Baud Rate: The number of signaling elements (or symbol changes) transmitted per second.

For simple encoding schemes like NRZ and Manchester/Differential Manchester, each signaling element represents exactly one bit. However, the *rate* of signal changes required to represent these bits differs.

In NRZ, one bit corresponds to one signal level for the bit duration. In Manchester/Differential Manchester, one bit corresponds to a sequence of two signal levels (a transition) within the bit duration. Effectively, you need to make signal changes at twice the bit rate in Manchester encoding compared to the most efficient scenario in NRZ (alternating bits).

While the minimum theoretical bandwidth for NRZ is $\frac{R}{2}$, practical implementations often require closer to $R$ for reliable detection. For Manchester and Differential Manchester, the theoretical minimum is $R$, but practical implementations might require closer to $2R$. The comparison of *minimum theoretical* bandwidths is the standard way to compare their inherent efficiency, showing Manchester requires twice that of the *minimum* NRZ.

Was this answer helpful?

Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

  2. A mass is attached to a spring that hangs vertically. The extension produced in the spring is 6 cm on Earth. The acceleration due to gravity on the surface of the Moon is one-sixth of its value on the surface of the Earth. The extension of the spring on the Moon would be:

  3. Directions: Each item in this section consists of a sentence with an underlined word followed by four words (a), (b), (c), and (d). Select the option that is opposite in meaning to the underlined word and mark your response in your Answer Sheet accordingly.

    The deluge affected the population.
  4. The major source of vitamins and minerals for vegetarians is

  5. Which of the following statements about the Deccan Riots Commission is/are correct?

    1. The Commission did not hold enquiries in the districts which were not affected.

    2. The Commission did record the statements of ryots, sahukars and eye-witnesses.

    Select the correct answer using the code given below:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App