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Question

What is the maximum value that can be assigned to one quad (octet) of an address in an IPv4 addressing system?

The correct answer is
255

IPv4 Octet Maximum Value Explained

An IPv4 address is structured into four parts, called octets or quads, separated by dots (e.g., 192.168.1.1). Each octet represents a sequence of 8 bits.

Understanding Binary Representation

In computing, a bit can hold one of two values: 0 or 1. An 8-bit sequence allows for $2^8$ unique combinations.

  • Calculation: $2^8 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 256$ possible combinations.

Determining the Maximum Value

These 256 combinations represent numerical values starting from 0. Therefore, the range of values for an 8-bit octet is from 0 to $2^8 - 1$.

  • Maximum Value = $2^8 - 1$
  • Maximum Value = $256 - 1$
  • Maximum Value = 255

Thus, the maximum value that can be assigned to a single octet (quad) in an IPv4 address is 255.

Final Answer Check

Comparing this result with the given options:

  • Option 1: 127 (Incorrect - This is the max value for a signed 8-bit integer, or the end of the loopback range)
  • Option 2: 128 (Incorrect)
  • Option 3: 255 (Correct)
  • Option 4: 256 (Incorrect - This is the total number of values, not the maximum value)

The maximum value is 255.

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Important Questions from IPv4

  1. An IP packet has arrived with the first 8 bits as 0100 0101. Which of the following is correct?

  2. What is the minimum length of a IP header?

  3. ____ addresses are reserved for multicasting.

  4. The IP address _______ is used by hosts when they are being booted.

  5. A classless address is given as 167.199.170.82/27. The number of addresses in the network is

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