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Question

What is the maximum addressing capability of Intel 8085?

The correct answer is

64 KB

Understanding Intel 8085 Addressing Capability

The addressing capability of a microprocessor refers to the total amount of memory it can access. This is determined by the number of address lines on the processor's address bus.

The Intel 8085 is a popular 8-bit microprocessor. It has separate buses for data and addresses. The data bus is 8 bits wide, meaning it can transfer 8 bits (1 byte) of data at a time. The address bus is used to specify the memory location or I/O port the CPU wants to access.

Intel 8085 Address Bus Size

A key characteristic of the Intel 8085 is its address bus size. The Intel 8085 has a 16-bit address bus. This means the processor can generate a 16-bit address.

Calculating Maximum Addressable Memory

The number of unique memory locations a processor can address is equal to $2^{\text{number of address lines}}$. For the Intel 8085 with its 16-bit address bus, the total number of addressable memory locations is:

Number of locations = $2^{16}$

To calculate this value:

  • $2^{10} = 1024$ (which is 1 KB - KiloByte)
  • $2^{16} = 2^{10} \times 2^6$
  • $2^{16} = 1024 \times 64$
  • $2^{16} = 65536$

So, the Intel 8085 can address $65536$ unique memory locations. Each location typically stores 1 byte of data.

Therefore, the total addressable memory is $65536$ bytes.

Converting Bytes to Kilobytes

Memory capacity is often expressed in kilobytes (KB). 1 KB is equal to $1024$ bytes.

To convert $65536$ bytes to KB:

Memory in KB = $\frac{65536 \text{ bytes}}{1024 \text{ bytes/KB}}$

Memory in KB = $64$ KB

Thus, the maximum addressing capability of the Intel 8085 microprocessor is 64 KB.

Analyzing the Options

Let's look at the given options:

  • 64 KB
  • 1 MB
  • 4 KB
  • 32 KB

Our calculation shows the maximum addressing capability is 64 KB, which matches the first option.

Revision Table: Key Intel 8085 Specifications

Specification Value Impact on System
Data Bus Size 8 bits Determines how much data is transferred at once (1 byte).
Address Bus Size 16 bits Determines the maximum addressable memory space ($2^{16}$ locations).
Maximum Addressable Memory 64 KB ($2^{16}$ bytes) The total memory (RAM or ROM) the processor can access.
Clock Speed Around 3 MHz to 6 MHz Affects the execution speed of instructions.
Architecture 8-bit microprocessor Basic data and instruction processing unit.

Additional Information on Microprocessor Addressing

The size of the address bus is a fundamental characteristic of any CPU as it directly limits the amount of physical memory the CPU can address. Here are some related concepts:

  • Memory Addressing: The process by which the CPU locates a specific memory location to read data from or write data to. Each location has a unique address.
  • Physical Address Space: The total range of memory addresses that a CPU can generate on its address bus. For the 8085, this is $0000\text{H}$ to $FFFF\text{H}$, covering 65536 locations.
  • Memory Organization: How the total addressable memory is arranged, typically into RAM (Random Access Memory) and ROM (Read-Only Memory) sections, based on the system design. The 64 KB space in an 8085 system is divided among these, along with any memory-mapped I/O.
  • Larger Address Spaces: Modern processors have much larger address buses (e.g., 32-bit, 64-bit) to support gigabytes or terabytes of memory.
    • A 32-bit address bus supports $2^{32}$ bytes = 4 GB.
    • A 64-bit address bus supports $2^{64}$ bytes (a very large number, far exceeding current physical memory limits).

Understanding the address bus size and its relation to memory capacity is crucial for designing and programming systems based on a specific microprocessor like the Intel 8085.

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Important Questions from Architecture of 8085

  1. Which of the following interrupts is non-maskable in 8085 microprocessor?

  2. In a microprocessor, the term 'pipelining' refers to

  3. The clock frequency of an 8085 microprocessor is 5 MHz. If the time required to execute an instruction is 1.4 μs, then the number of T-states needed for executing the instruction is

  4. In an 8085 microprocessor, which one of the following instructions changes the content of the accumulator?

  5. Which stack is used in 8085 microprocessors?

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