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Question

What is the length of each link in a revenue chain?

The correct answer is
\(2\frac{1}{16}\) feet

Revenue Chain Link Length Explained

Understanding specific measurements related to business concepts is important. This question asks about the precise length of each individual link within what is termed a 'revenue chain'. While the exact context or application of this 'revenue chain' isn't provided, the question requires identifying a specific standard measurement.

Correct Link Length Measurement

The standard length defined for each link in a revenue chain is provided in the options. Based on the correct answer, the length is:

  • \(2\frac{1}{16}\) feet

This measurement signifies a specific dimension. Let's look closer at this value:

  • The unit of measurement is feet.
  • The value is a mixed number: 2 whole feet plus \(\frac{1}{16}\) of a foot.
  • To express this as a single fraction, we convert the mixed number: \(2\frac{1}{16} = \frac{(2 \times 16) + 1}{16} = \frac{32 + 1}{16} = \frac{33}{16}\) feet.
  • In decimal form, \(\frac{33}{16}\) feet is equal to 2.0625 feet.

Comparing Other Options

It is helpful to understand why the other options are not the correct measurement for a revenue chain link:

  • Option 1: 0.6 feet - This measurement is significantly shorter than \(2\frac{1}{16}\) feet.
  • Option 2: 20 cm - To compare this with the correct answer, we convert centimeters to feet. Since 1 foot is approximately 30.48 cm, 20 cm is roughly \(\frac{20}{30.48} \approx 0.656\) feet. This is also much shorter.
  • Option 3: 1 feet - This length is also considerably less than the specified \(2\frac{1}{16}\) feet.

Therefore, the specific length required for each link in a revenue chain is \(2\frac{1}{16}\) feet.

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Important Questions from Linear Measurement

  1. The engineer's chain is typically:

  2. Correction for pull or tension in a tape is given by

  3. Cross-staff is used for:

  4. The scale of a drawing is given as 1 : 20.

    What is the representative fraction?

  5. An Engineer measured the distance between two locations on a plan having a scale of 1 cm = 50 m as 600 m. Later, however, he found that he used a wrong scale of 1 cm = 30 m to measure the distance. The true distance between the locations is:

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