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Question

What is the largest number that divides 627, 15630 and 3128 and leaves remainders of 2, 5 and 3, respectively?

The correct answer is

625

Finding the Largest Number with Specific Remainders

The question asks for the largest number that divides three given numbers, 627, 15630, and 3128, leaving specific remainders: 2, 5, and 3, respectively.

Let the largest number be $N$. According to the problem statement:

  • When 627 is divided by $N$, the remainder is 2. This means $627 - 2$ is perfectly divisible by $N$.
  • When 15630 is divided by $N$, the remainder is 5. This means $15630 - 5$ is perfectly divisible by $N$.
  • When 3128 is divided by $N$, the remainder is 3. This means $3128 - 3$ is perfectly divisible by $N$.

So, $N$ must be a common divisor of the numbers obtained by subtracting the remainders:

  • $627 - 2 = 625$
  • $15630 - 5 = 15625$
  • $3128 - 3 = 3125$

Since we are looking for the largest number that divides these three numbers, we need to find the Highest Common Factor (HCF) or Greatest Common Divisor (GCD) of 625, 15625, and 3125.

Calculating the HCF (Greatest Common Divisor)

To find the HCF of 625, 15625, and 3125, we can use the prime factorization method.

Let's find the prime factors of each number:

  • Prime factorization of 625: \[625 = 5 \times 125 = 5 \times 5 \times 25 = 5 \times 5 \times 5 \times 5 = 5^4\]
  • Prime factorization of 15625: \[15625 = 5 \times 3125 = 5 \times 5 \times 625 = 5 \times 5 \times 5^4 = 5^6\]
  • Prime factorization of 3125: \[3125 = 5 \times 625 = 5 \times 5^4 = 5^5\]

Now we identify the common prime factors and their lowest powers. The only common prime factor is 5. The powers of 5 are $5^4$, $5^6$, and $5^5$. The lowest power is $5^4$.

Therefore, the HCF of 625, 15625, and 3125 is $5^4$.

Calculating the value of $5^4$:

\[5^4 = 5 \times 5 \times 5 \times 5 = 25 \times 25 = 625\]

So, the largest number that divides 627, 15630, and 3128 leaving remainders 2, 5, and 3 respectively is 625.

Summary of Calculation

Original Number Remainder Number Perfectly Divisible Prime Factorization
627 2 \(627 - 2 = 625\) \(5^4\)
15630 5 \(15630 - 5 = 15625\) \(5^6\)
3128 3 \(3128 - 3 = 3125\) \(5^5\)

HCF (625, 15625, 3125) = Lowest power of common prime factors = \(5^4 = 625\).

Final Answer Determination

The largest number is 625.

Revision Table: HCF with Remainders

Concept Explanation Application
Problem Type Finding HCF when numbers leave specific remainders. If $N$ divides $A$ leaving remainder $r$, then $N$ divides $A-r$.
Method Subtract remainders from original numbers. Find HCF of the resulting numbers. Numbers become 625, 15625, 3125. Find HCF(625, 15625, 3125).
HCF Calculation Prime factorization or Euclidean algorithm. Using prime factorization: \(625=5^4\), \(15625=5^6\), \(3125=5^5\). HCF is \(5^4=625\).

Additional Information: Understanding HCF

The Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), of two or more non-zero integers is the largest positive integer that divides each of the integers without leaving a remainder.

Methods to find HCF include:

  • Prime Factorization Method:
    1. Find the prime factorization of each number.
    2. Identify the common prime factors.
    3. For each common prime factor, take the lowest power that appears in any of the factorizations.
    4. Multiply these lowest powers together to get the HCF.
  • Euclidean Algorithm:
    1. To find the HCF of two numbers, divide the larger number by the smaller number and find the remainder.
    2. Replace the larger number with the smaller number and the smaller number with the remainder.
    3. Repeat the process until the remainder is 0. The last non-zero remainder is the HCF.
    4. For more than two numbers, find the HCF of two numbers, then find the HCF of the result and the next number, and so on.

In this problem, since all numbers are powers of 5, prime factorization was the most straightforward method.

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Important Questions from Divisibility and Remainder

  1. If a five digit number 247xy is divisible by 3, 7 and 11, then what is the value of (2y - 8x)?

  2. If the seven-digit number 94x29y6 is divisible by 72, then what is the value of (2x + 3y) for x ≠ y ?

  3. Find the greatest value of b so that 30a68b (a > b) is divisible by 11.

  4. What is the remainder when the product of 335, 608 and 853 is divided by 13?

  5. What is the least square number which is exactly divisible by 2, 3, 10, 18 and 20?
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