What is the Highest Common Factor of 2 3× 3 5and 3 3× 5 2?
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The Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), of two or more numbers is the largest positive integer that divides each of the numbers without leaving a remainder. When numbers are given in their prime factorization form, finding the HCF is straightforward.
To find the HCF of two numbers expressed as a product of prime powers:
We are given two numbers:
Let's identify the prime factors in each number and their powers:
| Prime Factor | Power in $2^3 \times 3^5$ | Power in $3^3 \times 5^2$ |
|---|---|---|
| 2 | 3 | (Not present, equivalent to power 0) |
| 3 | 5 | 3 |
| 5 | (Not present, equivalent to power 0) | 2 |
Now, let's find the common prime factors and their lowest powers:
The only common prime factor is 3, and its lowest power is 3. Therefore, the HCF is $3^3$.
Based on the analysis, the HCF is the product of the common prime factors raised to their lowest powers.
Common prime factor: 3
Lowest power of 3: 3
HCF = $3^3$
The Highest Common Factor of $2^3 \times 3^5$ and $3^3 \times 5^2$ is $3^3$. This means $3^3$ is the largest number that can divide both $2^3 \times 3^5$ and $3^3 \times 5^2$ completely without leaving a remainder.
| Concept | Description |
|---|---|
| HCF | Largest number dividing two or more numbers exactly. |
| Prime Factorization | Expressing a number as a product of its prime factors. |
| Finding HCF from Prime Factors | Product of lowest powers of common prime factors. |
While HCF uses the lowest powers of common prime factors, the Least Common Multiple (LCM) uses the highest powers of all prime factors present in either number. For the same numbers, $2^3 \times 3^5$ and $3^3 \times 5^2$:
So, the LCM would be $2^3 \times 3^5 \times 5^2$. Understanding both HCF and LCM helps in solving various problems involving fractions, ratios, and number theory.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Four prime numbers are arranged in ascending order. The product of the first three numbers is 255 and that of the last three is 1955. The largest prime number is:
Find the number of all prime numbers less than 55.