What is the discharge (m3/s) from circular pipe having diameter 0.5 m and velocity of flow of 10 m/s?
1.96
The question asks us to determine the discharge from a circular pipe given its diameter and the velocity of the flow within it. Discharge, often denoted by 'Q', is the volume of fluid passing through a cross-sectional area per unit time. It is a fundamental concept in fluid mechanics.
The discharge (Q) is calculated using the simple formula:
\(Q = \text{Area} \times \text{Velocity}\)
Where:
The pipe is circular. The cross-sectional area (\(A\)) of a circle is given by the formula:
\(A = \pi r^2\)
Where \(r\) is the radius of the circle. We are given the diameter (\(D\)), and the radius is half the diameter:
\(r = \frac{D}{2}\)
So, the area can also be calculated as:
\(A = \pi \left(\frac{D}{2}\right)^2 = \frac{\pi D^2}{4}\)
We are given:
First, let's calculate the radius:
\(r = \frac{0.5 \text{ m}}{2} = 0.25 \text{ m}\)
Next, let's calculate the cross-sectional area of the pipe:
\(A = \pi r^2 = \pi (0.25 \text{ m})^2\)
\(A = \pi \times 0.0625 \text{ m}^2\)
Using the value of \(\pi \approx 3.14159\):
\(A \approx 3.14159 \times 0.0625 \text{ m}^2 \approx 0.19635 \text{ m}^2\)
Now, we can calculate the discharge using the formula \(Q = A \times V\):
\(Q = 0.19635 \text{ m}^2 \times 10 \text{ m/s}\)
\(Q = 1.9635 \text{ m}^3\text{/s}\)
The calculated discharge is approximately 1.9635 m\({}^3\)/s. Let's look at the given options:
The calculated value \(1.9635 \text{ m}^3\text{/s}\) is closest to the option \(1.96 \text{ m}^3\text{/s}\).
Therefore, the discharge from the circular pipe is approximately 1.96 m\({}^3\)/s.
| Concept | Definition | Formula (for Circular Pipe) |
|---|---|---|
| Discharge (Q) | Volume of fluid passing a point per unit time | \(Q = A \times V\) |
| Cross-sectional Area (A) | Area perpendicular to flow direction | \(A = \frac{\pi D^2}{4}\) or \(A = \pi r^2\) |
| Velocity (V) | Speed of fluid flow | Given or calculated (e.g., from continuity equation) |
| Diameter (D) | Distance across the pipe through center | Given |
| Radius (r) | Distance from center to edge of pipe | \(r = D/2\) |
Discharge is also known as volume flow rate. It represents how much volume of fluid moves through a system over a specific period. The units of discharge are typically volume per unit time, such as m\({}^3\)/s, L/s, or ft\({}^3\)/s (cfs). Knowing the discharge is crucial in many engineering applications, including designing pipe networks, managing water resources, and analyzing fluid transport systems.
The continuity equation in fluid dynamics is based on the principle of mass conservation and often relates discharge in different sections of a pipe or channel:
\(Q_1 = Q_2\)
or
\(A_1 V_1 = A_2 V_2\)
This means that for an incompressible fluid in a pipe with varying cross-sectional area, the product of the area and velocity remains constant, implying that if the area decreases, the velocity must increase, and vice versa, to maintain the same flow rate.
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