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Question

What is the condition for maximum discharge through a circular channel section using Manning’s formula?

The correct answer is

0.938D

Maximum Discharge in a Circular Channel using Manning's Formula

Understanding the conditions for maximum discharge in open channels is crucial in hydraulic engineering. For a circular channel, the discharge rate is not maximum when the channel is flowing full (i.e., depth equals diameter). Instead, due to the relationship between the flow area and wetted perimeter, the maximum discharge occurs at a specific depth less than the full depth.

Manning's formula for discharge \( Q \) is given by:

\[ Q = \frac{1}{n} A R^{2/3} S^{1/2} \]

Where:

  • \( Q \) is the discharge
  • \( n \) is Manning's roughness coefficient
  • \( A \) is the cross-sectional area of flow
  • \( R \) is the hydraulic radius \( (A/P) \)
  • \( P \) is the wetted perimeter
  • \( S \) is the channel slope

For a given channel (fixed diameter \( D \), roughness \( n \), and slope \( S \)), the discharge \( Q \) depends on the flow depth \( y \), which determines \( A \) and \( P \), and hence \( R \). To find the depth for maximum discharge, we need to find the depth \( y \) that maximizes the term \( A R^{2/3} \), or \( A^{5/3} / P^{2/3} \), with respect to the flow depth \( y \).

This optimization involves expressing \( A \) and \( P \) in terms of the channel diameter \( D \) and the flow depth \( y \) (often parameterized using an angle related to the wetted portion of the circle). Differentiating \( A^{5/3} / P^{2/3} \) with respect to the relevant parameter (like flow depth or the central angle) and setting the derivative to zero yields the condition for maximum discharge.

The mathematical analysis shows that the maximum discharge through a circular channel section using Manning's formula occurs when the depth of flow \( y \) is approximately 0.938 times the diameter \( D \).

The condition for maximum discharge is therefore approximately:

\[ y \approx 0.938D \]

This is a standard result obtained from the calculus-based optimization of the discharge equation for a circular section.

Comparing this condition with the given options, we see that the option corresponding to 0.938D represents the depth condition for maximum discharge.

Note that this depth (approx. 0.938D) is different from the depth for maximum velocity, which occurs at approximately 0.81D.

Let's look at the options provided:

  • 0.938D
  • 0.105R
  • 0.5D
  • 0.093R

The option 0.938D directly matches the derived condition for maximum discharge in a circular channel.

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Important Questions from Design of Sewer

  1. Surface run off caused by rainfall which is conveyed through sewer is called _______.

  2. A watershed of area 90 hectares has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the water shed and of intensity 4.5 cm/hr creates a peak discharge of

  3. Which one of the following is NOT a factor responsible for sewer corrosion?

  4. For a circular sewer running partially full, the proportionate wetted perimeter is given by:

  5. The maximum discharge through a circular channel takes place when depth of flow is equal to:

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