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Question

What is the coefficient of restitution (e) for elastic impact?

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1

Understanding Coefficient of Restitution in Collisions

The coefficient of restitution, often denoted by the symbol 'e', is a measure of how much kinetic energy is conserved in a collision between two objects. It's essentially the ratio of the relative speed of separation after the collision to the relative speed of approach before the collision.

The formula for the coefficient of restitution (e) between two objects (object 1 and object 2) with initial velocities \(u_1\) and \(u_2\) and final velocities \(v_1\) and \(v_2\) is given by:

$$ e = \frac{v_2 - v_1}{u_1 - u_2} $$

Here, \(u_1 - u_2\) is the relative speed of approach (assuming object 1 is catching up to object 2, so \(u_1 > u_2\)). The term \(v_2 - v_1\) is the relative speed of separation after the collision.

Coefficient of Restitution for Different Types of Collisions

The value of 'e' helps us classify different types of collisions:

  • Elastic Collision: In a perfectly elastic collision, kinetic energy is conserved along with momentum. The objects rebound without any loss of energy to heat or deformation.
  • Inelastic Collision: In an inelastic collision, kinetic energy is not conserved. Some kinetic energy is lost, usually converted into other forms like heat, sound, or deformation energy. Momentum is still conserved.
  • Perfectly Inelastic Collision: This is an extreme case of an inelastic collision where the objects stick together after the collision and move as a single body. In this case, the relative speed of separation is zero.

Elastic Impact: Value of Coefficient of Restitution

For an elastic impact or elastic collision, the kinetic energy before the collision is equal to the kinetic energy after the collision. This specific condition corresponds to a coefficient of restitution of 1.

In an elastic collision, the relative speed of separation is equal to the relative speed of approach. Mathematically, this means:

$$ v_2 - v_1 = u_1 - u_2 $$

Substituting this into the formula for 'e':

$$ e = \frac{u_1 - u_2}{u_1 - u_2} = 1 $$

Thus, for elastic impact, the coefficient of restitution (e) is equal to 1.

Analyzing the Given Options

Let's look at the provided options in the context of the coefficient of restitution for elastic impact:

  • Option 1: 0 - This value of 'e' corresponds to a perfectly inelastic collision.
  • Option 2: >1 - This value (>1) is theoretically possible in some scenarios involving energy release (like an explosion), but not for simple passive collisions where objects deform and rebound.
  • Option 3: 1 - This value of 'e' corresponds precisely to a perfectly elastic collision.
  • Option 4: <0 - A negative value for 'e' is not physically meaningful in standard collision analysis, as it implies the relative velocity direction is reversed after the collision in a way that isn't captured by the standard definition of separation and approach speeds. The relative speeds are usually considered in magnitude or direction relative to each other, leading to e ≥ 0.

Based on the definition and properties of elastic impact, the coefficient of restitution is 1.

Revision Table: Coefficient of Restitution Summary

Collision Type Kinetic Energy Coefficient of Restitution (e)
Elastic Collision Conserved e = 1
Inelastic Collision Not Conserved (Lost) 0 < e < 1
Perfectly Inelastic Collision Maximum Loss e = 0

Additional Information on Collisions and Restitution

Understanding the coefficient of restitution is key in mechanics and physics, especially when dealing with impacts and collisions. It helps predict the outcome of collisions and the energy transformations involved.

  • Momentum is always conserved in any collision (as long as no external forces are acting).
  • Kinetic energy is only conserved in perfectly elastic collisions (e=1).
  • Most real-world collisions are inelastic, meaning 0 < e < 1. Some energy is always lost due to factors like friction, heat, and sound.
  • The concept of the coefficient of restitution is used in various applications, from designing safety features in vehicles to analyzing sports equipment performance.
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Important Questions from Kinematics and Kinetics

  1. A body of mass 10 kg moving with a velocity of 1 m/s is acted upon by a force of 50 N for two seconds. The final velocity will be:

  2. A car is traveling on a curved road of radius 300 m at speed of 15 m/s. The normal and tangential components of acceleration respectively are given by:

  3. A ball is dropped on a smooth horizontal surface from height ‘h’. What will be the height of rebounce after second impact, if coefficient of restitution between ball and surface is ‘e’?

  4. How much force will be exerted by the floor of the lift on a passenger of 80 kg mass when lift is accelerating downward at 0.81 m/s2?

  5. The angular motion of a disc is defined by the relation (θ = 3t + t3), where θ is in radians and t is in seconds. What will be the angular position after 2 seconds?

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