What is the arithmetic mean of first 8 multiples of 13?
58.5
The first 8 multiples of 13 are obtained by multiplying 13 by the first 8 positive integers (1 through 8).
The sum of these multiples can be calculated efficiently. Notice that the sum is $13 \times (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8)$.
The sum of the first $n$ natural numbers is given by the formula $\frac{n(n+1)}{2}$. For $n=8$, the sum is:
Sum of integers from 1 to 8 = $\frac{8(8+1)}{2} = \frac{8 \times 9}{2} = \frac{72}{2} = 36$.
Therefore, the sum of the first 8 multiples of 13 is:
Sum = $13 \times 36 = 468$.
Alternatively, using the arithmetic progression sum formula $S_n = \frac{n}{2}(a_1 + a_n)$, where $n=8$, $a_1=13$, and $a_8=104$:
Sum = $\frac{8}{2}(13 + 104) = 4 \times 117 = 468$.
The arithmetic mean is the sum of the numbers divided by the count of the numbers.
Arithmetic Mean = $\frac{\text{Sum of the first 8 multiples}}{\text{Number of multiples}}$
Arithmetic Mean = $\frac{468}{8}$
Arithmetic Mean = $58.5$.
The arithmetic mean of the first 8 multiples of 13 is 58.5.
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