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Question

$ \cosec \theta - \sin \theta = p^3 $ and $ \sec \theta - \cos \theta = q^3 $

What is tanθ equal to ?

This question was previously asked in
CDS 2 2026 Maths Question Paper (13-Sep-2026)
The correct answer is
\(\frac{q}{p}\)

Solving for tan θ: Given Trigonometric Equations

We are given two trigonometric equations:

  • \(\ \ \cosec \theta - \sin \theta = p^3\)
  • \(\ \ \sec \theta - \cos \theta = q^3\)

We need to find the value of \(\tan \theta\).

Simplifying the Given Equations

Rewrite the equations using fundamental trigonometric identities (\(\ \cosec \theta = \frac{1}{\sin \theta}\), \(\ \sec \theta = \frac{1}{\cos \theta}\), \(\ 1 - \sin^2 \theta = \cos^2 \theta\), \(\ 1 - \cos^2 \theta = \sin^2 \theta\)).

  1. \(\ \frac{1}{\sin \theta} - \sin \theta = p^3\)
    \(\implies \frac{1 - \sin^2 \theta}{\sin \theta} = p^3\)
    \(\implies \frac{\cos^2 \theta}{\sin \theta} = p^3\) (Equation 1)
  2. \(\ \frac{1}{\cos \theta} - \cos \theta = q^3\)
    \(\implies \frac{1 - \cos^2 \theta}{\cos \theta} = q^3\)
    \(\implies \frac{\sin^2 \theta}{\cos \theta} = q^3\) (Equation 2)

Deriving tan θ

To find \(\tan \theta\), we can divide Equation 2 by Equation 1:

\(\frac{q^3}{p^3} = \frac{(\frac{\sin^2 \theta}{\cos \theta})}{(\frac{\cos^2 \theta}{\sin \theta})}\)

Simplify the right side:

\(\frac{q^3}{p^3} = \frac{\sin^2 \theta}{\cos \theta} \times \frac{\sin \theta}{\cos^2 \theta}\)

\(\frac{q^3}{p^3} = \frac{\sin^3 \theta}{\cos^3 \theta}\)

Recognize that \(\ \frac{\sin^3 \theta}{\cos^3 \theta} = (\tan \theta)^3\):

\(\frac{q^3}{p^3} = (\tan \theta)^3\)

Take the cube root of both sides:

\(\tan \theta = \sqrt[3]{\frac{q^3}{p^3}}\)

\(\tan \theta = \frac{q}{p}\)

Conclusion

Therefore, \(\tan \theta\) is equal to \(\frac{q}{p}\). This matches Option B.

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Similar Questions

  1. If \(\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2+...}}}} = \text{cosec}\theta\), then what is \(\sin\theta\) equal to?

  2. If \(2 \tan\theta = \sec^2\theta-2\), where \(0 < \theta < \pi /2\), then what is \(\cot\theta\) equal to?
  3. What is \(\frac{\tan^2 \alpha}{\tan^2 \beta}\) equal to?
  4. If \(\alpha\) and \(\beta\) are complementary angles, then which one of the following is correct?
  5. What is \(\sec\theta\) equal to?
  6. What is \(\tan\theta\) equal to?
  7. What is the relation between \(p\) and \(q\)?
  8. What is $\tan\theta + \cot\theta$ equal to?
  9. Consider the following statements :
    1. In a triangle ABC, if \(\sin A + \sin B + \sin C = \frac{3\sqrt{3}}{2}\), then the triangle can be equilateral.
    2. In a triangle ABC, if \(\cos A + \cos B + \cos C = \frac{3}{2}\), then the triangle can be equilateral.
    Which of the statements given above is/are correct?
  10. What is \((1 + \tan\alpha \tan\beta)^2 + (\tan\alpha - \tan\beta)^2\) equal to ?


Important Questions from Trigonometry

  1. (secθ + tanθ)/(secθ - tanθ)  is equal to:

  2. If tan 45°, cot θ then the value of θ, in radians is

  3. ABC is a triangle If sin (A+B)/2 = √3/2, then the value of sin C/2 is

  4. The angles of elevation of the top of a temple, from the foot and the top of a building 30 m high, are 60° and 30° respectively. Then height of the temple is

  5. The value of sin θ and cos θ when the angle θ is 0 ≤ θ ≤ 90°, is ______

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