Let 12 $ (\tan \theta + \cot \theta) = 25 $, where $ 45^\circ < \theta < 90^\circ $
Given the equation \(12 (\tan \theta + \cot \theta) = 25\) and the range \(45^\circ < \theta < 90^\circ\). We need to find the value of \((\sin \theta - \cos \theta)\).
Rewrite \(\tan \theta\) and \(\cot \theta\) using \(\sin \theta\) and \(\cos \theta\):
Substitute into the equation:
\(12 \left( \frac{\sin \theta}{\cos \theta} + \frac{\cos \theta}{\sin \theta} \right) = 25\)
Find a common denominator:
\(12 \left( \frac{\sin^2 \theta + \cos^2 \theta}{\sin \theta \cos \theta} \right) = 25\)
Apply the identity \(\sin^2 \theta + \cos^2 \theta = 1\):
\(12 \left( \frac{1}{\sin \theta \cos \theta} \right) = 25\)
\(\frac{12}{\sin \theta \cos \theta} = 25\)
Solve for the product \(\sin \theta \cos \theta\):
\(\sin \theta \cos \theta = \frac{12}{25}\)
Consider the square of the target expression \((\sin \theta - \cos \theta)\):
\((\sin \theta - \cos \theta)^2 = \sin^2 \theta - 2 \sin \theta \cos \theta + \cos^2 \theta\)
Group terms and use the identity \(\sin^2 \theta + \cos^2 \theta = 1\):
\((\sin \theta - \cos \theta)^2 = (\sin^2 \theta + \cos^2 \theta) - 2 \sin \theta \cos \theta\)
\((\sin \theta - \cos \theta)^2 = 1 - 2 \sin \theta \cos \theta\)
Substitute the value of \(\sin \theta \cos \theta\):
\((\sin \theta - \cos \theta)^2 = 1 - 2 \left( \frac{12}{25} \right) = 1 - \frac{24}{25}\)
\((\sin \theta - \cos \theta)^2 = \frac{25 - 24}{25} = \frac{1}{25}\)
Take the square root of both sides:
\(\sin \theta - \cos \theta = \pm \sqrt{\frac{1}{25}} = \pm \frac{1}{5}\)
Analyze the sign based on the given range \(45^\circ < \theta < 90^\circ\):
Therefore, \((\sin \theta - \cos \theta)\) must be positive.
Select the positive value:
\(\sin \theta - \cos \theta = \frac{1}{5}\)
The value of 5 sin 14° sec 76° + 3 cot 15° cot 75° + 2 tan 45° is:
If two complimentary angles are in the ratio of 4 : 5, find the greater angle.
If \(\frac{\sin\spaceθ \space+\space \cos\spaceθ} {\sin \spaceθ \space-\space \cos \spaceθ} = \frac{\sqrt3 \space-\space 1}{\sqrt3 \space+\space 1} \) , then the angle θ is
If tan α = 1/2, tan β = 1/3, then find α + β.
Simplify: sin (A + B) sin (A – B)