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Question

Volume of coarse aggregate in $m^3$ present in $1.0 m^3$ of $1 : 1.5 : 3$ concrete mix made by volume batching is ________

Concrete Mix Ratio

The given concrete mix ratio is $1 : 1.5 : 3$. This represents the proportions of Cement : Fine Aggregate : Coarse Aggregate by volume.

Volume Batching Calculation

In volume batching, the volumes are measured directly according to the specified ratio.

  • Total parts in the mix = $1 + 1.5 + 3 = 5.5$ parts.
  • The proportion of coarse aggregate is 3 parts out of the total 5.5 parts.
  • For a total concrete volume of $1.0 m^3$, the volume of coarse aggregate is calculated as:

$ \text{Volume of Coarse Aggregate} = \left( \frac{\text{Parts of Coarse Aggregate}}{\text{Total Parts}} \right) \times \text{Total Volume of Concrete} $

$ \text{Volume of Coarse Aggregate} = \left( \frac{3}{5.5} \right) \times 1.0 m^3 $

$ \text{Volume of Coarse Aggregate} = \frac{30}{55} m^3 = \frac{6}{11} m^3 $

$ \text{Volume of Coarse Aggregate} \approx 0.5454... m^3 $

Final Volume Determination

The calculated volume of coarse aggregate is approximately $0.545 m^3$. This value falls within the range specified in the answer.

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