The scalar triple product $\vec{a} \cdot (\vec{b} \times \vec{c})$ is calculated using the determinant of the matrix formed by the components of the vectors $\vec{a}$, $\vec{b}$, and $\vec{c}$.
The scalar triple product equals the determinant:
$ \vec{a} \cdot (\vec{b} \times \vec{c}) = \begin{vmatrix} 2 & -3 & 4 \\ 1 & 2 & -3 \\ 3 & 4 & -1 \end{vmatrix} $Expand the determinant along the first row:
$ = 2 \begin{vmatrix} 2 & -3 \\ 4 & -1 \end{vmatrix} - (-3) \begin{vmatrix} 1 & -3 \\ 3 & -1 \end{vmatrix} + 4 \begin{vmatrix} 1 & 2 \\ 3 & 4 \end{vmatrix} $Calculate the 2x2 determinants:
Substitute these values back into the expansion:
$ = 2(10) + 3(8) + 4(-2) $ $ = 20 + 24 - 8 $ $ = 44 - 8 $ $ = 36 $The scalar triple product $\vec{a} \cdot (\vec{b} \times \vec{c})$ is 36.
What is the length of projection of the vector \(\rm \hat{i}+2 \hat{j}+3 \hat{k}\) on the vector \(\rm2 \hat{i}+3 \hat{j}-2 \hat{k}\) ?
Consider the following in respect of the vectors \(\rm \vec{a}=(0,1,1)\) and \(\rm \vec{b}=(1,0,1) \) :
1. The number of unit vectors perpendicular to both \(\rm \vec{a}\) and \(\rm \vec{b}\) is only one.
2. The angle between the vectors is \(\frac{\pi}{3}\).
Which of the statements given above is/are correct?
Consider the following points :
1. (-1, -3, 1)
2. (-1, 3, 2)
3. (-2, 5, 3)
Which of the above points lie on the line joining A and B ?
What is the magnitude of \(\overrightarrow{A B}\) ?
If \({\rm{\vec d}} = {\rm{x\hat i}} + {\rm{y\hat j}} + {\rm{z\hat k}}\) , then which of the following equations is/are correct?
1. y – x = 4
2. 2z – 3 = 0
Select the correct answer using the code given below: