Using the given information, calculate the mass defect of \( ^{16}_{8}O \) nucleus in MeV/\( c^2 \). Mass of electron, \( m_e = 0.00055u \) Mass of proton, \( m_p = 1.00727u \) Mass of neutron, \( m_n = 1.00866u \) Experimental mass of nucleus = 15.99053u \( 1u = 931.5 \) MeV/\( c^2 \) (where \( u \) = atomic mass unit) Choose the correct answer:
127.5 MeV/\( c^2 \)
The mass defect (\( \Delta m \)) of a nucleus is the difference between the total mass of its constituent nucleons (protons and neutrons) and the actual measured mass of the nucleus. This missing mass is converted into energy that holds the nucleus together, known as the binding energy.
We are given the following information for the \( ^{16}_{8}O \) nucleus:
The total mass of the protons and neutrons if they were separate is calculated by summing the masses of 8 protons and 8 neutrons.
Total mass of nucleons = (Number of protons \( \times \) Mass of proton) + (Number of neutrons \( \times \) Mass of neutron)
Total mass of nucleons = \( (8 \times m_p) + (8 \times m_n) \)
Substituting the given values:
\( (8 \times 1.00727u) + (8 \times 1.00866u) \)
\( 8.05816u + 8.06928u \)
Total mass of nucleons = \( 16.12744u \)
The mass defect is the difference between the calculated total mass of individual nucleons and the experimental mass of the nucleus.
\( \Delta m = \) (Total mass of individual nucleons) - (Experimental mass of nucleus)
\( \Delta m = 16.12744u - 15.99053u \)
\( \Delta m = 0.13691u \)
We use the given conversion factor \( 1u = 931.5 \) MeV/\( c^2 \) to convert the mass defect from atomic mass units to MeV/\( c^2 \).
\( \Delta m \) in MeV/\( c^2 \) = \( \Delta m \) in u \( \times \) Conversion factor
\( \Delta m \) in MeV/\( c^2 \) = \( 0.13691u \times 931.5 \) MeV/\( c^2 \)/u
\( \Delta m \) in MeV/\( c^2 \) \( \approx 127.539665 \) MeV/\( c^2 \)
Rounding this value gives approximately \( 127.5 \) MeV/\( c^2 \).
Thus, the mass defect of the \( ^{16}_{8}O \) nucleus is approximately \( 127.5 \) MeV/\( c^2 \).
| Concept | Definition | Formula/Relation |
|---|---|---|
| Mass Defect (\( \Delta m \)) | The difference between the mass of individual nucleons and the mass of the nucleus. | \( \Delta m = (Z m_p + N m_n) - M_{nucleus} \) |
| Binding Energy (\( E_b \)) | The energy equivalent of the mass defect, holding the nucleus together. | \( E_b = \Delta m \cdot c^2 \) (often calculated using \( \Delta m \) in u and converting using \( 1u \approx 931.5 \) MeV/\( c^2 \)) |
| Atomic Mass Unit (u) | A standard unit of mass used for atoms and molecules, defined as 1/12 of the mass of a carbon-12 atom. | \( 1u \approx 1.6605 \times 10^{-27} \) kg \( \approx 931.5 \) MeV/\( c^2 \) |
Mass defect is a crucial concept in nuclear physics. It arises from Einstein's mass-energy equivalence principle, \( E=mc^2 \). When protons and neutrons combine to form a nucleus, some mass is converted into energy. This energy, the binding energy, is released during the formation of the nucleus and is required to break the nucleus apart into its constituent nucleons.
The process involves calculating the theoretical mass based on the number of protons and neutrons and their individual masses, and then comparing it to the experimentally measured mass of the nucleus. The difference is the mass defect, which is then converted to energy units (like MeV) using the conversion factor based on \( c^2 \).
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