Under the influence of a uniform magnetic field, a charged particle moves with a constant speed v in a circle of radius r. The time period of the revolution of the particle:
Is independent of both v and r
The time period of a charged particle moving in a uniform magnetic field is given by:
T = (2πm) / (qB),
which shows that the time period is independent of both velocity (v) and radius (r). It only depends on the charge (q), mass (m) of the particle, and the magnetic field (B).
Thus, the correct answer is (b).
Important Questions from Moving Charge and Magnetism
A square-shaped wire loop of side L is carrying a current I. What is the magnetic field at the point of intersection of diagonals of the square wire loop?
The magnitude of a magnetic force on a current-carrying conductor is given by:
Under the influence of a uniform magnetic field, a charged particle moves with a constant speed v in a circle of radius r. The time period of the revolution of the particle:
A square-shaped wire loop of side L is carrying a current I. What is the magnetic field at the point of intersection of diagonals of the square wire loop?
The magnitude of a magnetic force on a current-carrying conductor is given by:
