Ultimate bearing capacity (qf) of a square footing 2.5 m wide resting at 1.5 m depth in a sandy soil having unit weight γ = 18 kN/m3, Nq = 33, Nγ = 48, using factor of safety as 3, will be
585 kN/m2
The question asks for the ultimate bearing capacity (\(q_f\)) of a square footing. However, the calculated value matching the options is the gross safe bearing capacity (\(q_{safe}\)) derived from the ultimate bearing capacity divided by a factor of safety. We will proceed by first calculating the ultimate bearing capacity using a standard method and then applying the factor of safety to see which option is matched.
For sandy soil (\(c=0\)), the ultimate bearing capacity (\(q_f\)) using Terzaghi's formula for a square footing is given by:
$$q_f = c N_c s_c + q N_q s_q + 0.5 \gamma B N_\gamma s_\gamma$$
Since \(c=0\) for sandy soil, the formula simplifies to:
$$q_f = q N_q s_q + 0.5 \gamma B N_\gamma s_\gamma$$
Where:
Using the simplified formula for square footing in sand:
$$q_f = \gamma D_f N_q + 0.4 \gamma B N_\gamma$$
The surcharge pressure at the footing depth is:
$$q = \gamma \times D_f$$
$$q = 18 \text{ kN/m}^3 \times 1.5 \text{ m}$$
$$q = 27 \text{ kN/m}^2$$
Now substitute the values into the ultimate bearing capacity formula:
$$q_f = q N_q + 0.4 \gamma B N_\gamma$$
$$q_f = (27 \text{ kN/m}^2 \times 33) + (0.4 \times 18 \text{ kN/m}^3 \times 2.5 \text{ m} \times 48)$$
First term: \(27 \times 33 = 891\) kN/m\(^2\)
Second term: \(0.4 \times 18 \times 2.5 \times 48 = 0.4 \times 45 \times 48 = 18 \times 48 = 864\) kN/m\(^2\)
$$q_f = 891 \text{ kN/m}^2 + 864 \text{ kN/m}^2$$
$$q_f = 1755 \text{ kN/m}^2$$
This value of \(1755 \text{ kN/m}^2\) is the ultimate bearing capacity, which is the maximum pressure the soil can support before failure.
The factor of safety (FS) is used to determine the safe bearing capacity, which is the ultimate bearing capacity divided by the factor of safety. While the question asks for ultimate bearing capacity, the option matching the calculation using the given FS is the safe bearing capacity.
$$q_{safe} = \frac{q_f}{\text{FS}}$$
$$q_{safe} = \frac{1755 \text{ kN/m}^2}{3}$$
$$q_{safe} = 585 \text{ kN/m}^2$$
The calculated gross safe bearing capacity is \(585 \text{ kN/m}^2\), which matches one of the given options. It appears the question intended to ask for the safe bearing capacity or the provided options correspond to the safe bearing capacity calculation.
| Parameter | Value | Unit |
|---|---|---|
| Footing Width (B) | 2.5 | m |
| Footing Depth (Df) | 1.5 | m |
| Unit Weight (\(\gamma\)) | 18 | kN/m\(^3\) |
| Nq | 33 | - |
| N\(\gamma\) | 48 | - |
| Factor of Safety (FS) | 3 | - |
| Surcharge (q) | 27 | kN/m\(^2\) |
| Ultimate Bearing Capacity (qf) | 1755 | kN/m\(^2\) |
| Gross Safe Bearing Capacity (qsafe) | 585 | kN/m\(^2\) |
| Term | Definition | Calculation Example |
|---|---|---|
| Ultimate Bearing Capacity (qf) | Maximum pressure soil can withstand at the footing base before shear failure occurs. | Using formulas like Terzaghi's: \(q_f = cN_c + qN_q + 0.5\gamma BN_\gamma\) (with shape factors) |
| Net Ultimate Bearing Capacity (qnf) | Ultimate bearing capacity minus the surcharge pressure at footing level. | \(q_{nf} = q_f - q\) |
| Gross Safe Bearing Capacity (qsafe) | Ultimate bearing capacity divided by a factor of safety. Design pressure allowed on the soil. | \(q_{safe} = q_f / \text{FS}\) |
| Net Safe Bearing Capacity (qnsafe) | Net ultimate bearing capacity divided by a factor of safety. Can also be \(q_{safe} - q\). | \(q_{nsafe} = q_{nf} / \text{FS}\) or \(q_{nsafe} = q_{safe} - q\) |
| Factor of Safety (FS) | A factor used to reduce ultimate capacity to safe capacity, accounting for uncertainties. Typically between 2.5 and 3.5 for shear failure. | Given as 3 in this problem. |
Bearing capacity factors \(N_c, N_q, N_\gamma\) are dimensionless quantities that depend on the soil's angle of internal friction (\(\phi\)) and the footing shape. They are derived from theoretical analyses of soil failure mechanisms. Different researchers (like Terzaghi, Meyerhof, Hansen, Vesic) have proposed different sets of these factors and corresponding formulas and shape factors.
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