To solve this problem, we need to determine the probability of the sum of outcomes on the top faces of two rolled dice being either 7 or 10.
First, let's consider the total number of possible outcomes when two dice are rolled. Each die has 6 faces, which results in a total of 6 \times 6 = 36 possible outcomes.
Next, we'll find the number of outcomes where the sum is 7. These combinations are:
- (1, 6)
- (2, 5)
- (3, 4)
- (4, 3)
- (5, 2)
- (6, 1)
There are 6 outcomes where the sum is 7.
Now, let's find the number of outcomes where the sum is 10. These combinations are:
- (4, 6)
- (5, 5)
- (6, 4)
There are 3 outcomes where the sum is 10.
To find the probability of the sum being either 7 or 10, we add the favorable outcomes:
The total number of favorable outcomes = 6 (sum = 7) + 3 (sum = 10) = 9.
The probability is therefore given by dividing the number of favorable outcomes by the total number of possible outcomes:
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{9}{36} = \frac{1}{4} = 0.25
The correct answer is 0.25, which corresponds to the given option.
Important Questions from Probability
The probability of being 53 Sundays in year 2020 is-
Three dice are thrown randomly. The probability of coming 3 in at least one die is
The probability of having 53 Tuesdays in an ordinary year is:
Two dice are thrown simultaneously The probability of getting the sum 2 or 8 or 12 is
If two balanced dice are tossed once, the probability of the event, that the sum of the integers coming on the upper sides of the two dice is 9, is
