We are given two datasets:
We need to find the variance of the combined dataset.
First, calculate the variance for each dataset:
Calculate the mean of the combined dataset ($\bar{x}_{comb}$):
$ \bar{x}_{comb} = \frac{n_1 \bar{x}_1 + n_2 \bar{x}_2}{n_1 + n_2} $ $ \bar{x}_{comb} = \frac{(10 \times 8) + (20 \times 8)}{10 + 20} = \frac{80 + 160}{30} = \frac{240}{30} = 8 $Since both original means are 8, the combined mean is also 8.
The formula for the combined variance ($s_{comb}^2$) of two datasets is:
$ s_{comb}^2 = \frac{n_1 s_1^2 + n_2 s_2^2 + n_1 (\bar{x}_1 - \bar{x}_{comb})^2 + n_2 (\bar{x}_2 - \bar{x}_{comb})^2}{n_1 + n_2} $Since $\bar{x}_1 = \bar{x}_{comb} = 8$ and $\bar{x}_2 = \bar{x}_{comb} = 8$, the terms involving the difference between means are zero:
$ (\bar{x}_1 - \bar{x}_{comb})^2 = (8 - 8)^2 = 0 $ $ (\bar{x}_2 - \bar{x}_{comb})^2 = (8 - 8)^2 = 0 $The formula simplifies to:
$ s_{comb}^2 = \frac{n_1 s_1^2 + n_2 s_2^2}{n_1 + n_2} $Substitute the known values into the simplified formula:
$ s_{comb}^2 = \frac{(10 \times 1) + (20 \times 4)}{10 + 20} $ $ s_{comb}^2 = \frac{10 + 80}{30} $ $ s_{comb}^2 = \frac{90}{30} $ $ s_{comb}^2 = 3 $The variance of the combined dataset is 3.
When Mean deviation is divided by the average used in finding out the mean deviation itself, the resulting quantity is described as_____________.
.
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Coefficient of Dispersion | (I) Standard deviation as a percentage of mean |
| (B) Standard Deviation | (II) Mean of squared deviations of individual scores from mean |
| (C) Coefficient of variation | (III) Variance in terms of mean |
| (D) Variance | (IV) Positive square root of variance |
Two data set of sizes 9 and 6 have standard deviation 3 and 4 respectively and arithmetic means 3 respectively. The standard deviation of combined data set of size 15 is