To determine the motion of one projectile as seen from another, we analyze their relative acceleration. This depends on the accelerations of the individual projectiles in a common inertial frame.
Let $\vec{a}_1$ be the acceleration of the first projectile and $\vec{a}_2$ be the acceleration of the second projectile. The problem states that both projectiles experience the same acceleration:
$ \vec{a}_1 = \vec{a}_2 $
The acceleration of projectile 1 as observed from the frame of reference of projectile 2 is the relative acceleration, $\vec{a}_{12}$:
$ \vec{a}_{12} = \vec{a}_1 - \vec{a}_2 $
Substituting the given condition $\vec{a}_1 = \vec{a}_2$ into the equation:
$ \vec{a}_{12} = \vec{a}_1 - \vec{a}_1 = \vec{0} $
A relative acceleration of zero ($ \vec{a}_{12} = \vec{0} $) means that the relative velocity between the two projectiles is constant. This implies:
In essence, from the perspective of one projectile, the other moves with uniform velocity. Uniform velocity motion results in a straight line path (or a stationary point if relative velocity is zero).
Therefore, the motion of one projectile as seen from another, when both have the same acceleration, is always a straight line.
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |