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Question

Two numbers are in the ratio of 15: 11. If their HCF is 13. Find the numbers.

The correct answer is
195 and 143

To solve this problem, we need to find two numbers that are in the ratio of 15:11 and have a Highest Common Factor (HCF) of 13. Let's go through the solution step-by-step.

Let the two numbers be \(15x\) and \(11x\), based on the given ratio 15:11.

The HCF of \(15x\) and \(11x\) is given as 13. Therefore, \(x\) must be 13 since 13 is the greatest number that divides both numbers entirely. Thus, we can write:

  • The first number: \(15x = 15 \times 13 = 195\)
  • The second number: \(11x = 11 \times 13 = 143\)

Now we have identified the numbers: 195 and 143.

Let's verify that these numbers meet both conditions (ratio and HCF):

  • Ratio: \(\frac{195}{143} = \frac{15}{11}\), which confirms the ratio is 15:11.
  • HCF: Since we found \(x = 13\), the HCF condition holds true as the HCF is indeed 13.

Thus, the two numbers are 195 and 143, which matches the correct answer option.

Therefore, the correct answer is 195 and 143.

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Important Questions from LCM and HCF

  1. The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:

  2. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

  3. Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?

  4. What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?

  5. Which of the following is a pair of co-primes?

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