Two dice are thrown simultaneously. What is the probability of getting a sum, which is a multiple of 4.
The question asks for the probability of an event occurring when two dice are thrown simultaneously. Specifically, we need to find the probability that the sum of the numbers shown on the two dice is a multiple of 4.
When two standard six-sided dice are thrown, each die can land on any number from 1 to 6. The total number of possible outcomes is the product of the outcomes for each die.
The sample space consists of all possible pairs of outcomes, such as (1,1), (1,2), ..., (6,6).
We need to find the pairs of outcomes where the sum of the numbers is a multiple of 4. The possible sums range from \(1+1=2\) to \(6+6=12\). The multiples of 4 within this range are 4, 8, and 12.
The pairs that sum to 4 are:
There are 3 outcomes where the sum is 4.
The pairs that sum to 8 are:
There are 5 outcomes where the sum is 8.
The pair that sums to 12 is:
There is 1 outcome where the sum is 12.
The total number of favorable outcomes is the sum of the outcomes for sums 4, 8, and 12.
Total Favorable Outcomes = 3 + 5 + 1 = 9
The probability of an event is calculated using the formula:
$$ \text{Probability} = \dfrac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} $$
Plugging in the values we found:
$$ \text{Probability (Sum is a multiple of 4)} = \dfrac{9}{36} $$
The fraction \( \dfrac{9}{36} \) can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 9.
$$ \dfrac{9 \div 9}{36 \div 9} = \dfrac{1}{4} $$
The probability of getting a sum that is a multiple of 4 when two dice are thrown simultaneously is \( \dfrac{1}{4} \).
The probability of being 53 Sundays in year 2020 is-
Three dice are thrown randomly. The probability of coming 3 in at least one die is
The probability of having 53 Tuesdays in an ordinary year is:
Two dice are thrown simultaneously The probability of getting the sum 2 or 8 or 12 is
If two balanced dice are tossed once, the probability of the event, that the sum of the integers coming on the upper sides of the two dice is 9, is