The resistance ($R$) of a conductor depends on its material's resistivity ($\rho$), its length ($L$), and its cross-sectional area ($A$). The relationship is given by the formula:
$R = \rho \frac{L}{A}$
We have two conductors made of the same material, meaning their resistivity ($\rho$) is the same. Let the properties of the first conductor be $L_1, A_1, R_1$ and the second be $L_2, A_2, R_2$.
The problem states that the conductors have equal resistance, so $R_1 = R_2$. We can set the expressions for their resistances equal to each other:
$ \rho \frac{L}{A_1} = \rho \frac{2L}{A_2} $
Since $\rho$ and $L$ are non-zero, we can cancel them from both sides:
$ \frac{1}{A_1} = \frac{2}{A_2} $
To find the ratio $A_1 : A_2$, we rearrange the equation:
$ \frac{A_1}{A_2} = \frac{1}{2} $
Therefore, the ratio of their cross-sectional areas ($A_1 : A_2$) is 1:2.
Which of the following statements are correct about the electrical resistance and resistivity of a wire?
1. Both quantities depend on the area of cross-section of the wire
2. Both depend on the temperature
3. Resistance of the wire is directly proportional to the resistivity of the wire
4. Resistivity of the wire is directly proportional to the length of the
wire
Select the correct answer using the code given below:
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