Two ampere hour (Ah) is equal to how many Coulombs?
7200 C
The question asks to convert a quantity given in ampere-hours (Ah) into Coulombs (C). This involves understanding the relationship between charge, current, and time, which are fundamental concepts in electricity.
An ampere-hour (Ah) is a unit of electrical charge. It represents the amount of electrical charge transferred by a steady current of one ampere (A) flowing for one hour (h). It's commonly used to measure the capacity of batteries.
The Coulomb (C) is the SI unit of electrical charge. It is defined as the amount of charge transported in one second (s) by a constant current of one ampere (A).
From the definition of the Coulomb, we can see the relationship:
\(1 \text{ Coulomb} = 1 \text{ Ampere} \times 1 \text{ Second}\)
Or, using symbols:
\(1 \text{ C} = 1 \text{ A} \times 1 \text{ s}\)
This means that one Ampere is equivalent to one Coulomb per second:
\(1 \text{ A} = 1 \text{ C/s}\)
To convert ampere-hours (Ah) to Coulombs (C), we need to express the time unit (hour) in the standard SI unit of time, which is seconds. There are 60 minutes in an hour, and 60 seconds in a minute. So, the number of seconds in one hour is:
\(1 \text{ hour} = 60 \text{ minutes/hour} \times 60 \text{ seconds/minute} = 3600 \text{ seconds}\)
Now we can convert 1 ampere-hour (Ah) to Coulombs (C):
So, 1 Ampere-hour can be written as:
\(1 \text{ Ah} = 1 \text{ A} \times 1 \text{ h}\)
Substitute the values in terms of C/s and s:
\(1 \text{ Ah} = (1 \text{ C/s}) \times (3600 \text{ s})\)
The 's' units cancel out, leaving us with Coulombs:
\(1 \text{ Ah} = 3600 \text{ C}\)
The question asks for the equivalent of two ampere-hours (2 Ah) in Coulombs. Since we know that 1 Ah is equal to 3600 C, we can find the value for 2 Ah by multiplying the value of 1 Ah by 2:
\(2 \text{ Ah} = 2 \times (1 \text{ Ah})\)
\(2 \text{ Ah} = 2 \times (3600 \text{ C})\)
Performing the multiplication:
\(2 \text{ Ah} = 7200 \text{ C}\)
Therefore, two ampere-hours is equal to 7200 Coulombs.
The conversion relies on the definitions of the units involved. Ampere is charge per unit time (Coulombs per second). Ampere-hour is current multiplied by time. By converting the time unit from hours to seconds, we get the total charge in Coulombs.
Key relationship:
\(\text{Charge (C)} = \text{Current (A)} \times \text{Time (s)}\)
Conversion factor:
\(1 \text{ hour} = 3600 \text{ seconds}\)
Calculation for 2 Ah:
\(2 \text{ Ah} = 2 \text{ A} \times 1 \text{ h} = 2 \text{ A} \times 3600 \text{ s} = 7200 \text{ C}\)
| Unit | Represents | Relationship |
|---|---|---|
| Ampere (A) | Electric Current | Charge per unit time (\(1 \text{ A} = 1 \text{ C/s}\)) |
| Coulomb (C) | Electric Charge | Base unit derived from Ampere and second (\(1 \text{ C} = 1 \text{ A} \cdot \text{ s}\)) |
| Ampere-hour (Ah) | Electric Charge (convenience unit) | Current × Time (\(1 \text{ Ah} = 3600 \text{ C}\)) |
Based on the calculation, 2 Ah is equal to 7200 C.
| Unit | Symbol | Quantity | Definition/Relationship |
|---|---|---|---|
| Coulomb | C | Electric Charge (Q) | Base SI unit derived from A and s. \(1 \text{ C} = 1 \text{ A} \cdot \text{ s}\) |
| Ampere | A | Electric Current (I) | Base SI unit. \(1 \text{ A} = 1 \text{ C/s}\) |
| Second | s | Time (t) | Base SI unit |
| Ampere-hour | Ah | Electric Charge (Q) | Non-SI unit. \(1 \text{ Ah} = 3600 \text{ C}\) |
Understanding electrical units is crucial in physics and engineering. Here are some related concepts:
The ampere-hour (Ah) is a practical unit for charge, especially in battery applications, as it directly relates to how long a device can draw a certain current before the battery is depleted. However, for standard scientific calculations, the Coulomb (C) is the preferred unit for electric charge.
In ideal case, the charging current for 200 Ah battery would be-
Which of the following is an example of a primary battery?
Which of the following statement is correct for primary cell with regards to secondary cell?
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