This problem involves finding the perimeter of one triangle ($\triangle$ ABC) given information about a similar triangle ($\triangle$ PQR) and the relationship between their sides.
When two triangles are similar, like $\triangle$ ABC and $\triangle$ PQR ($\triangle$ ABC ~ $\triangle$ PQR), their corresponding sides are in the same ratio. A key property of similar triangles is that the ratio of their perimeters is equal to the ratio of their corresponding sides.
Let $P_{ABC}$ be the perimeter of $\triangle$ ABC and $P_{PQR}$ be the perimeter of $\triangle$ PQR.
The property states:
$$ \frac{P_{ABC}}{P_{PQR}} = \frac{\text{Side of } \triangle \text{ ABC}}{\text{Corresponding Side of } \triangle \text{ PQR}} $$
Since $\triangle$ ABC ~ $\triangle$ PQR, the side BC in $\triangle$ ABC corresponds to the side QR in $\triangle$ PQR.
We are given:
First, find the ratio of the corresponding sides:
$$ \text{Ratio of Sides} = \frac{\text{BC}}{\text{QR}} = \frac{4 \text{ cm}}{8 \text{ cm}} = \frac{1}{2} $$
Now, use the property that the ratio of the perimeters is equal to the ratio of the corresponding sides:
$$ \frac{P_{ABC}}{P_{PQR}} = \frac{\text{BC}}{\text{QR}} $$
Substitute the known values into the formula:
$$ \frac{P_{ABC}}{32 \text{ cm}} = \frac{1}{2} $$
To find the perimeter of $\triangle$ ABC ($P_{ABC}$), multiply both sides of the equation by 32 cm:
$$ P_{ABC} = \frac{1}{2} \times 32 \text{ cm} $$
$$ P_{ABC} = 16 \text{ cm} $$
Therefore, the perimeter of $\triangle$ ABC is 16 cm.
In the following question, select the related number from the given alternatives.
198 : 66 :: ?
Select the set in which the numbers are related in the same way as are the numbers of the following sets.
(15, 135, 6)(12, 84, 5)
Kinematic similarity between model and prototype is the similarity of