Train travel time between stations A and B is 39 hours. Every day a pair of trains leave from A to B and B to A at 6 AM. If the service starts on a Monday, on which earliest day will the same train rakes start the journeys again from their original stations?
Friday
This problem involves calculating the round trip time for a train rake and determining the earliest day it can start its journey again from its original station, considering a fixed daily departure time.
Let's track the journey of a train rake that starts from station A towards station B.
The train leaves station A on Monday at 6 AM. The travel time from A to B is given as 39 hours.
To find the arrival time at station B, we add 39 hours to the departure time (Monday 6 AM):
So, the train rake arrives at station B on Tuesday at 9 PM.
This train rake is now at station B. To start its return journey to station A, it must depart from B. Trains depart from B to A every day at 6 AM.
Since the train arrived at B on Tuesday at 9 PM, it cannot depart on Tuesday at 6 AM (as it arrived too late). The earliest it can depart from station B is the next scheduled departure, which is Wednesday at 6 AM.
The return journey from B to A also takes 39 hours. Let's calculate the arrival time back at station A:
So, the train rake arrives back at station A on Thursday at 9 PM.
This train rake is now back at its original station A. To start its journey to B again, it must depart from A. Trains depart from A to B every day at 6 AM.
Since the train arrived back at A on Thursday at 9 PM, it cannot depart on Thursday at 6 AM (as it arrived too late). The earliest it can depart from station A is the next scheduled departure, which is Friday at 6 AM.
The same logic applies to the train rake that starts from station B towards station A on Monday 6 AM. It will arrive at A on Tuesday 9 PM, depart back to B on Wednesday 6 AM, arrive back at B on Thursday 9 PM, and be ready to depart for A again on Friday 6 AM.
Both train rakes complete their round trips and are back at their original stations by Thursday 9 PM. The earliest they can start their next journey from their original stations is the next scheduled departure time, which is Friday 6 AM.
Therefore, the earliest day the same train rakes will start their journeys again from their original stations is Friday.
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is: