Three numbers which are co-prime to each other are such that the product of the first two is 391 and that of the last two is 943. Find the middle number.
23
Let the three numbers be a, b, and c. We are given that a and b are co-prime, b and c are co-prime, and a, b, and c are co-prime. Product of first two numbers: ab = 391 Product of last two numbers: bc = 943 We need to find the value of b. 391 = 17 * 23 943 = 23 * 41 Since ab = 391 and bc = 943, and a, b, and c are co-prime, the common factor is b = 23.
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