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Question

Three numbers which are co-prime to each other are such that the product of the first two is 391 and that of the last two is 943. Find the middle number.

The correct answer is

23

Let the three numbers be a, b, and c. We are given that a and b are co-prime, b and c are co-prime, and a, b, and c are co-prime. Product of first two numbers: ab = 391 Product of last two numbers: bc = 943 We need to find the value of b. 391 = 17 * 23 943 = 23 * 41 Since ab = 391 and bc = 943, and a, b, and c are co-prime, the common factor is b = 23.

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Important Questions from Number System

  1. Consider the following statements :

    1. (25)! + 1 is divisible by 26

    2. (6)! + 1 is divisible by 7

    Which of the above statements is/are correct ?

  2. If the sum S is divided by 8, what is the remainder ?  

  3. If the sum S is divided by 60, what is the remainder ?

  4. Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.

  5. How many composite numbers are there from 53 to 97 ?

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